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Softa [21]
3 years ago
12

Which step follows the identification of the problem in the technological design process?

Physics
1 answer:
STALIN [3.7K]3 years ago
5 0
The answer is research.

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What is mean by "an electrically-charged object is quantized" ? and which physicist is accredited with the quantization of charg
PIT_PIT [208]

It means that electric charge exists in integral multiples of an elementary unit of charge rather taking on continuous values.

Since Millikan was the first to measure the value of the electronic charge in his famous "oil drop" experiment, he may be the one given credit for discovering quantization of charge.

8 0
3 years ago
A stone is dropped at t = 0. A second stone, with twice the mass of the first, is dropped from the same point at t = 181 ms. How
lara [203]

Answer:

the center of mass is 316,670m bellow the release point.

Explanation:

First, we must find the distance at which the objects are in time t = 360s

We will use the formula for vertical distance in free fall

h=v_{0}t+\frac{1}{2} gt^2

v_{0} is the initial velocity, is 0 for both stones since they were just dropped.

g is acceleration of gravity and t is time (g=9.81m/s^2)

At t=360s the first stone has been falling for the entire 360 seconds, its position h1 is:

h_{1}=\frac{1}{2} (9.82m/s^2)(360s^2)=635,688m

And at 360 seconds the second stone has been fallin fort= 360s -181 s = 179s, so its position h2 is:

h_{2}=\frac{1}{2} (9.81m/s^2)(179)^2=157,161.1m

And finally using the equation for the center of mass:

CM=\frac{m_{1}h_{1}+m_{2}h_{2}}{m_{1}+m_{2}}

We know that the mass of the second stone is twice the mass of the first stone so:

m_{1}=m\\m_{2}=2m

replacing these values in the equation for the center of mass

CM=\frac{mh_{1}+2mh_{2}}{m+2m}

CM=\frac{m(h_{1}+2h_{2})}{3m}=\frac{h_{1}+2h_{2}}{3}

Finally, replacing the values we found fot h1 and h2:

CM=\frac{635,688m+2(157,161.1m)}{3}=316,670m

the center of mass is 316,670m bellow the release point.

8 0
4 years ago
How are frequency,wavelength and pitch related
nikdorinn [45]
Hi there!

The frequency and wavelength of a wave can determine the pitch of the wave.
For example, if I had a sound wave with low frequency and a long wavelength, I'd have a lower pitched sound.

Hope this helps!
4 0
3 years ago
At atmospheric pressure, what is the characteristic boiling point of water, in degrees Celsius?
xxMikexx [17]
Water boils at 100 degrees Celsius at atmospheric pressure.
4 0
4 years ago
A woman can see clearly with her right eye only when objects are between 45 cm and 155 cm away. Prescription bifocals should hav
Yuri [45]

Answer:

Explanation:

given,

A woman can see object between 45 cm and 155 cm

glasses is 2 cm from the eye

to able to read a book distance = 25 cm

For the  object distant apart

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{\infty}+\dfrac{1}{-153}

\dfrac{1}{f} = - 6.53 \times 10^{-3}

hence, D = - 0.653  m

For the object at the near point

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{23} +\dfrac{1}{-43}

\dfrac{1}{f}= 0.0202 cm

hence, D = 2.02 m

8 0
3 years ago
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