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3 years ago

a girl of mass 40 kg wearing high heel of radius 3mm. find the pressure exerted by her on the ground. [answer the question fast]

Physics

1 answer:

kakasveta [241]3 years ago

7 0

You should calculate 40 kg and the radius 3mm.

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A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder

Stella [2.4K]

Answer:

The temperature change per compression stroke is 32.48°.

Explanation:

Given that,

Angular frequency = 150 rpm

Stroke = 2.00 mol

Initial temperature = 390 K

Supplied power = -7.9 kW

Rate of heat = -1.1 kW

We need to calculate the time for compressor

Using formula of compression

$\terxt{time for compression}=\text{time for half revolution}$

$\terxt{time for compression}=\dfrac{1}{2}\times T$

$\terxt{time for compression}=\dfrac{1}{2}\times \dfrac{1}{f}$

Put the value into the formula

$\terxt{time for compression}=\dfrac{1}{2}\times \dfrac{1}{150}\times60$

$\terxt{time for compression}=0.2\ sec$

We need to calculate the rate of internal energy

Using first law of thermodynamics

$U=Q-W$

$\dfrac{\Delta U}{\Delta t}=\dfrac{\Delta Q}{\Delta t}-\dfrac{\Delta W}{\Delta t}$

Put the value into the formula

$\dfrac{\Delta U}{\Delta t}=(-1.1)-(7.9)$

$\dfrac{\Delta U}{\Delta t}=6.8\ kW$

We need to calculate the temperature change per compression stroke

Using formula of rate of internal energy

$\dfrac{\Delta U}{\Delta t}=\dfrac{nc_{v}\Delta \theta}{\Delta t}$

$\Delta\theta=\dfrac{\Delta U}{\Delta t}\times\dfrac{\Delta t}{n\times c_{c}}$

Put the value into the formula

$\Delta \theta=6.8\times10^{3}\dfrac{0.2}{2.0\times20.93}$

$\Delta\theta=32.48^{\circ}$

Hence, The temperature change per compression stroke is 32.48°.

6 0

4 years ago

What is the best definition of luminous?

vagabundo [1.1K]

Answer:

the state of giving off light or glow.

8 0

3 years ago

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45.77 cubic inches to cubic centimeters

drek231 [11]

45.77 cubic inches is <span>753.8049cm³ cubic centimeters
</span><span>
</span>

5 0

4 years ago

A stone is dropped into water from a bridge 52 m above the water's

dusya [7]

Answer:

Its final velocity and how much time it takes to reach the water

Explanation:

The motion of the stone is a uniformly accelerated motion, so we can use the following suvat equation to determine its final velocity:

$v^2-u^2=2as$

where

v is the final velocity

u = 0 is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

s = 52 m is the distance covered during the fall

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0^2+2(9.8)(52)}=31.9 m/s$

We can also find how much time it takes to reach the water, using the equation

$v=u+at$

where

v = 31.9 m/s is the final velocity

u = 0 is the initial velocity

$a=g=9.8 m/s^2$

t is the time

And solving for t,

$t=\frac{v-u}{a}=\frac{31.9-0}{9.8}=3.26 s$

3 0

3 years ago

Can somone pls help asap???!!

joja [24]

I think its 1,2 sorry if wrong

7 0

3 years ago

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