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Ganezh [65]
2 years ago
8

What is the center and radius of the circle with equation (x+1)^2+y^2=81

Mathematics
1 answer:
CaHeK987 [17]2 years ago
4 0

The center of the circle is (-1 , 0) and the radius is 9 units

Step-by-step explanation:

The standard form of the equation of the circle  is

(x - h)² + (y - k)² = r², where

  • (h, k) are the coordinates of its center
  • r is its radius

This form of the equation is helpful, because you can easily find

the center and the radius.

Now let us solve the problem

∵ The equation is (x + 1)² + y² = 81

- By comparing the two equations

∵ (x - h)² + (y - k)² = r² and (x + 1)² + y² = 81

∴ x - h = x + 1

- Subtract x from both sides

∴ -h = 1

- Divide both sides by -1

∴ h = -1

∵ y - k = y

- Subtract y from both sides

∴ -k = 0

∴ k = 0

∵ h and k are the coordinates of the center of the circle

∴ The center of the circle is (-1 , 0)

∵ r² = 81

- Take √ for both sides

∴ r = 9

∴ The radius is 9 units

The center of the circle is (-1 , 0) and the radius is 9 units

Learn more:

You can learn more about the equation of the circle in brainly.com/question/1952668

#LearnwithBrainly

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