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3 years ago

What is answer from the periodic table please help very urgent due today

Chemistry

2 answers:

Alex73 [517]3 years ago

7 0

Answer:

Explanation:

You know this by looking at the number of protons and electrons which represents the atomic number.

Sindrei [870]3 years ago

5 0

Answer:

4 electron/proton

Explanation:

in first shell it has 2 electron

then in second shell it has 2 electron also

so add them together we get 4

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An archaeologist finds 14C in a sample of material to be decaying at 20 Geiger Counter clicks per second. A modern equivalent sa

Kay [80]

Answer:

17188 years

Explanation:

Recall the formula;

0.693/t1/2 = 2.303/t log(No/N)

t1/2 = half life of 14C

No = initial activity of 14C

N = activity of 14C at time t

t = age of the sample

Substituting values

0.693/5730= 2.303/t log(160/ 20)

1.21 * 10^-4= 2.0798/t

t = 2.0798/1.21 * 10^-4

t = 17188 years

4 0

3 years ago

Which statement explains why a molecule of CH4 is nonpolar?

Deffense [45]

The answer is the option (3) The geometric shape of a CH4 molecule distributes the charges geometrically. the CH4 is a tetrahedral with the Carbon atom in the center and the four H atoms in the vertices of the tetrahedral. The C-H bond angles are all identical which makes the molecule perfectly symmetrical and so any dipolar moment will cancel making the molecule non polar.

8 0

3 years ago

Read 2 more answers

PLEASE HELP 30 POINTS

Bas_tet [7]

Answer:

Because the rock is irregularly shaped, you used the displacement method to measure its volume. You used calculations to indirectly find the density of the objects.

PLZ Brainliest

8 0

3 years ago

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

4 years ago

Bronze is an alloy, which is what form of matter?

olga55 [171]

Compound is the answer I believe

8 0

3 years ago

What is answer from the periodic table please help very urgent due today ​

What is answer from the periodic table please help very urgent due today