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Sindrei [870]
1 year ago
7

Calcium propionate [Ca(CH₃CH₂COO)₂; calcium propanoate] is a mold inhibitor used in food, tobacco, and pharmaceuticals.(a) Use b

alanced equations to show whether aqueous calcium propionate is acidic, basic, or neutral.
Chemistry
1 answer:
tekilochka [14]1 year ago
4 0

We anticipate that the resulting aqueous solution will be basic.

<h3>What is the definition of a weak acid?</h3>

Weak acids are those that do not dissociate completely in solution. A weak acid is defined as any acid that is not a strong acid. A weak acid's strength is determined by how much it dissociates; the more it dissociates, the stronger the acid.

<h3>What exactly is a conjugate base?</h3>

A conjugate base is the base member, X-, of two compounds that transform into one another by gaining or losing a proton. In a chemical reaction, the conjugate base has the ability to gain or absorb a proton.

<h3>According to the given information:</h3>

Calcium propionate [Ca(CH₃CH₂COO)₂

We know that Calcium propionate dissolves completely in water.

So,

Ca(CH_3CH_2+COO)_2→Ca^2^+ +2CH_{3}CH_2COO−

Water can protonate the propionate anion. When everything is balanced,

CH_3CH_2\\COO−+H2O⇌CH_3CH_2COOH+OH−

We anticipate that the resulting aqueous solution will be basic.

To know more about Weak Acids and Conjugate Bases visit:

brainly.com/question/4483911

#SPJ4

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sertanlavr [38]

Answer:

3) NaCl.

Explanation:

<em>∵ ΔTf = iKf.m</em>

where, <em>i</em> is the van 't Hoff factor.

<em>Kf </em>is the molal depression freezing constant.

<em>m</em> is the molality of the solute.

<em>The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. </em>

<em></em>

  • For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<em>So, for sugar: i = 1.</em>

<em>∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.</em>

<em></em>

  • For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

<em>So, i for NaCl = 2.</em>

<em>∴ ΔTf for NaCl = iKf.m = (2)(Kf)(1.0 m) = 2 Kf.</em>

<em></em>

<em>So, the right choice is: 3) NaCl.</em>

<em></em>

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