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Sindrei [870]
1 year ago
7

Calcium propionate [Ca(CH₃CH₂COO)₂; calcium propanoate] is a mold inhibitor used in food, tobacco, and pharmaceuticals.(a) Use b

alanced equations to show whether aqueous calcium propionate is acidic, basic, or neutral.
Chemistry
1 answer:
tekilochka [14]1 year ago
4 0

We anticipate that the resulting aqueous solution will be basic.

<h3>What is the definition of a weak acid?</h3>

Weak acids are those that do not dissociate completely in solution. A weak acid is defined as any acid that is not a strong acid. A weak acid's strength is determined by how much it dissociates; the more it dissociates, the stronger the acid.

<h3>What exactly is a conjugate base?</h3>

A conjugate base is the base member, X-, of two compounds that transform into one another by gaining or losing a proton. In a chemical reaction, the conjugate base has the ability to gain or absorb a proton.

<h3>According to the given information:</h3>

Calcium propionate [Ca(CH₃CH₂COO)₂

We know that Calcium propionate dissolves completely in water.

So,

Ca(CH_3CH_2+COO)_2→Ca^2^+ +2CH_{3}CH_2COO−

Water can protonate the propionate anion. When everything is balanced,

CH_3CH_2\\COO−+H2O⇌CH_3CH_2COOH+OH−

We anticipate that the resulting aqueous solution will be basic.

To know more about Weak Acids and Conjugate Bases visit:

brainly.com/question/4483911

#SPJ4

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8090 [49]

Explanation:

(a) The molecular equations shows the equation in which all the species of the reactants and the products are in molecules and the net charge is zero.

The complete ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.

The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.

(b) If there is no spectator ions in the reaction, then the complete and the net ionic equations would be identical.

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ziro4ka [17]

Answer:

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that'll help ya

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Choose all of the answers that are correct when describing this atom.
gregori [183]
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