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Helga [31]
4 years ago
11

Draw a complete structural formula and a condensed structural formula for(a) three compounds of formula C3H8O (b) five compounds

of formula C3H6O

Chemistry
1 answer:
Marat540 [252]4 years ago
4 0

Answer:

Explanation:

A. Attached is a page which contain the structural formula of the three compounds of C3H80.

Condensed structural formula of C3H8O:

Propan-1-ol: CH3CH2CH2OH

Propan-2-ol: CH3CH(OH)CH3

Methoxy methane: CH3OCH2CH3

B. Attached are is a page which contain the structural formula of the three compounds of C3H60.

Condensed structural formula of C3H6O:

Propanal: CH3CH2CHO

Propanone: CH3COCH3

Cyclopropanol: (C3H5)OH

2-propen-1-ol: CH2CHCH2OH

1-propenol: CH3CHCHOH

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Here is the full question

Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 10 cm. The two liquids do not mix.

What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the density of glycerin is 1260 kg/m3and the density of alcohol is 790 kg/m3.

Express your answer in two significant figures and include the appropriate units (in cm)

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ΔH ≅ 3.73 cm

Explanation:

The pressure inside a liquid is known as hydrostatic pressure and which is represent by the formula:

P =   ρ × g × h

where;

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g is the gravitational constant

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From the question above;

For glycerine; we have:

density of glycerine = 1260 kg/m³

gravitational constant = 9.8 m/s²

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P_{(g)= 1260kg/m^3}*9.8m/s^2*h_g   ----- equation (1)

On the other hand for alcohol:

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P_{(a)= 790kg/m^3*9.8m/s^2*10           ----------- equation (2)

if we equate equation 1 and 2 together; we have

P_{(g)= P_{(a)

1260kg/m^3}*9.8m/s^2*h_g = 790kg/m^3*9.8m/s^2*10cm

Making h_g the subject of the formula, we have :

h_g= \frac{ 790kg/m^3*9.8m/s^2*10cm}{1260kg/m^3*9.8m/s^2}

h_g = 6.269 cm

The difference in the height denoted  by ΔH can therefore be calculated as:

ΔH = H_a-H_g

ΔH = 10cm - 6.269cm

ΔH = 3.731 cm

ΔH ≅ 3.73 cm           (to two significant figures)

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