How to show opposite sides on a parallelogram are congruent
1 answer:
Answer:
I am attaching a image to understand my proof.
Step-by-step explanation:
PROVE:-
AB = DC
AD = BC
∠ ABD = ∠ BDC (alternate angles are equal )
∠ DBC = ∠ ADB (alternate angles are equal )
∴ Δ ADB ≅ Δ CBD ( by ASA rule )
DC = BA ( corresponding sides of ≅ Δ )
AD = CB ( corresponding sides of ≅ Δ )
Hence it is proved that opposite sides of parallelogram are congruent )
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Answer:
<em>The correct option is: 82°</em>
Step-by-step explanation:
In the given diagram, two chords and
are intersecting.
According to the <u>Angle of intersecting chord theorem</u>, "<em>If two chords intersect inside a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle</em>."
That means here......
So, the measure of arc is 82°
