How to show opposite sides on a parallelogram are congruent
1 answer:
Answer:
I am attaching a image to understand my proof.
Step-by-step explanation:
PROVE:-
AB = DC
AD = BC
∠ ABD = ∠ BDC (alternate angles are equal )
∠ DBC = ∠ ADB (alternate angles are equal )
∴ Δ ADB ≅ Δ CBD ( by ASA rule )
DC = BA ( corresponding sides of ≅ Δ )
AD = CB ( corresponding sides of ≅ Δ )
Hence it is proved that opposite sides of parallelogram are congruent )
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For this case we have the following inequations:
1.5x-1> 6.5
7x + 3 <-25
Clearing x from each one we have:
For 1.5x-1> 6.5:
1.5x> 6.5 + 1
1.5x> 7.5
x> 7.5 / 1.5
x> 5
For 7x + 3 <-25:
7x <-25-3
7x <-28
x <-28/7
x <-4
The solution set is:
(inf, -4) U (5, inf)
Answer:
See attached image
1.5x-1> 6.5
7x + 3 <-25
Clearing x from each one we have:
For 1.5x-1> 6.5:
1.5x> 6.5 + 1
1.5x> 7.5
x> 7.5 / 1.5
x> 5
For 7x + 3 <-25:
7x <-25-3
7x <-28
x <-28/7
x <-4
The solution set is:
(inf, -4) U (5, inf)
Answer:
See attached image