Suppose f varies directly as g, and f varies inversely as h. Find g when f = 12 and h = 10, if g = 198 when h = –11 and f = –6.
Round your answer to the nearest hundredth, if necessary.
Question 5 options:
–360
–40
40
360
1 answer:
Answer:
360
Step-by-step explanation:
f varies directly as g
f = kg where k is the constant of variation
f varies inversely as h
f = kg/h
We know g = 198 when h = –11 and f = –6. Substituting in
-6 = k*198/(-11)
-6 =k*(-18)
Dividing each side by -18
-6/-18 = k*-18/-18
1/3 =k
Our equation is
f = 1/3 g/h
Letting f = 12 and h = 10
12 = 1/3 g/10
Multiply each side by 10
12*10 =1/3 g/10*10
120 = 1/3 g
Multiply each side by 3
120*3 =1/3 g *3
360 =g
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For this sequence, you can write this function:
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