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hammer [34]
2 years ago
13

55. The sum of an infinite geometric series is five times the value of the first term. What is the common ratio of the series?

Mathematics
1 answer:
myrzilka [38]2 years ago
8 0

Answer:

r = 4/5

Step-by-step explanation:

Formula

Sum of an infinite geometric series = a / (1 - r)

Givens

Sum = 5*a

a = a

r = ?

Solution

5a = a/(1 - r)                   Divide both sides by a

5a/a = a / (a * (1 - r)       The a's on the right cancel

5 = 1 / (1 - r)                    Multiply both sides by 1 - r

5*(1 - r) = 1*(1 - r)/(1 - r)   The 1 - r s on the right cancel

5*(1 - r) = 1                     Remove the brackets.

5 - 5r = 1                        Subtract 5 from both sides

5-5 - 5r = 1 - 5               Combine

-5r = - 4                          Divide by - 5

r = 4/5  

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Pleas help me alot of points​
alekssr [168]

Answer:

12

Step-by-step explanation:

its a square all sides of the square are the same so 48 divided by 4 is 12

5 points is not a lot of points

6 0
3 years ago
The sums that appear when two fair? four-sided dice? (tetrahedrons) with sides 1?, 2?, 3?, and 4 are tossed
Karolina [17]

Answer:

The possible sums are 2, 3, 4, 5, 6, 7 & 8 (but they're not all equally likely)

Step-by-step explanation:

For example, the only way to get a sum of 2 is to roll a 1 and then a 1

And the only way to get a sum of 8 is to roll a 4 and then a 4 (imagine you don't roll the two dice simultaneously; this will help you to see the "other possibilities" that aren't obvious at first)

The probability of rolling a sum of 2 = probability of rolling sum of 8 (1/16 probability for each)

If you roll a 1 then a 2, or a 2 then a 1, there are 2 ways to get a sum of 3

If you roll a 3 then a 1, a 2 then a 2, or a 1 then a 3, there are 3 ways to get a sum of 4

If you roll a 4 then a 1, a 3 then a 2, a 2 then a 3, or a 1 then a 4, there are 4 ways to get a sum of 5 (5 is the most likely sum)

If you roll a 4 then a 2, a 3 then a 3, or a 2 then a 4, there are 3 ways to get a sum of 6

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5 0
3 years ago
Please help me with questions 1 and 2
Nana76 [90]
1. 3/3 2. 3/4 the answer is 3/4
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%28x%20-%203%29%28x%20%2B%204%29%28x%20-%202%29%20%3D%200" id="TexFormula1" title="(x - 3)(x +
AlexFokin [52]

Answer:

Step-by-step explanation:

x-3 = 0

x = 3

x + 4 = 0

x = -4

x - 2 = 0

x = 2

x = 3, -4, 2

8 0
3 years ago
Isn’t it just 5? Why would it say check all that apply
LenKa [72]

Answer: 25^\frac{1}{2}

Step-by-step explanation:

25 = 5*5 or -5 * -5

yes, that is correct. However, you forgot another property of roots. Roots are simply exponential fractions.

\sqrt[n]{x^m}=x^\frac{m}{n}

Therefore, \sqrt{25} can also be rewritten as: 25^\frac{1}{2}. Notice that it cannot be -25 because that would be a negative square root which will give us an imaginary number.

4 0
3 years ago
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