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3 years ago

The sum of a number and 4 divided by 5

1 answer:

7 0

The sum of a number and 4 divided by 5 can be thought of the following:

A number - X

(X + 4)/5.

The algebraic expression would be (X+4)/5. If this is what you were looking for.

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Estimating Areas and Areas of Circles

umka21 [38]

Answer:

1)84 yd

2)63 in

3)7853.98 mm (round as you want)

4)153.94 ft

5)201.06 m

Step-by-step explanation:

3 0

3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

Standard notation for six and three tenths

AlexFokin [52]

Answer:

6 3/10 or as a decimal 6.3

6 0

3 years ago

-36 ÷ 4 A) 4 groups of 9 negatives B) 4 groups of 9 positives C) 9 groups of 4 negatives D) 9 groups of 4 positives

Valentin [98]

Answer:

A) 4 groups of 9 negatives

Step-by-step explanation:

-36/4

-9

This means we have 4 groups of 9 negatives

7 0

3 years ago

Subtract a+b from a-b

Anestetic [448]

Answer:

Step-by-step explanation:

EX: a=4

b=2

4-2-4+2=0

8 0

2 years ago