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4 years ago

Plz plz plz help❤I'll help back

Mathematics

2 answers:

jeka944 years ago

5 0

Ok so do u know how to use pemdas so the p stands for parentheses the e stands for exponents the M stand for multiplying the D stand for dividing the a stands for addition and the S stand for subtraction so the first step is to do the exponent so 3 times 3 times 3 wich gives u 9 so now ur next step would be to TO multiply 5 times 4 wich is 20 so ur equation would be like this 20+9-15 divided by 5 so ur next step is to divide 15 divided by 5 wich is 3 so ur final equation would look like this 20+9-3 now solve that and that's ur answer hope this helped

Rama09 [41]4 years ago

3 0

The answer is forty four 44

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If a cow has a mass of 9 × 10^2

kotykmax [81]

Answer:

a) The blue whale has about 200 times more mass

Step-by-step explanation:

(blue whale mass)/(cow mass) = (1.8×10^5 kg)/(9×10^2 kg)

... = (1.8/9)×10^(5-2)

... = 0.2×10^3

... = 200

The blue whale has about 200 times as much mass as a cow.

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Which letter on the number line represents 5 added to -4

UkoKoshka [18]

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3 years ago

The second floor of a tiny house has a living room in a bedroom. The floor plan shows a width of 8 ft in a total length of 24 ft

Keith_Richards [23]

Answer:

Expression 8 • 24 represents the total area.

Option A is correct.

Step-by-step explanation:

Width of living room = 8 ft

Length of living room = 24 ft

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$Area = 8\times24$

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6 0

3 years ago

The enrollments of all 13 public universities in the state of ohio are listed below. college enrollment university of akron 25,6

bekas [8.4K]

Answers:

(a) The enrollment data is a population
(b) Mean: 22,150.62
(c) Median: 18,670
(d) Range: 57,776
(e) Standard Deviation: 14,258.49

Explanations:

(a) As we noticed in the problem, the enrollment data is used for the study of the number of enrollments in all of the public universities in Ohio. Since the given enrollment data contains the number of enrollments in all of the public univeristies in Ohio, the enrollment data is a population.

(b) To compute the mean, we get the sum of all the data points and divide it by the number of data points.

Since,

Sum of all data points = 1725 + 4344 + 14655 + 15693 + 17338 + 18641 18670 + 20251 + 20839 + 25612 + 34187 + 36502 + 59,501
Sum of all data points = 287,958

and the number of data points = 13,

mean = 287,958 ÷ 13 = 22,150.62

(c) The median is computed when the data points are arranged from least to greatest and it is equal to either:

>> the middle number - if the number of data points is an odd number, or
>> the average of 2 middle numbers - if the number of data points is an even number

In the enrollment data, when the data points are arranged from lowest to highest, the following is the result:

1725, 4344, 14655, 15693, 17338, 18641, 18670, 20251, 20839, 25612, 34187, 36502, 59,501

Since the number of data points is 13 and 13 is an odd number, we find the middle number, which is the 7th lowest number = 18670.

Hence, the median is 18670.

(d) The range of the data is the difference between the highest data point and the lowest data point.

Since the highest data point is 59,501, the lowest data point is 1725 and their difference is 59,501 - 1725 = 57,776. The range of the enrollment data is 57,776.

(e) To compute for standard deviation,

>> First, we compute the squares of all the data points and find their sum:

Sum of the squares of data points = 1725² + 4344² + 14655² + 15693² + 17338² + 18641² + 18670² + 20251² + 20839² + 25612² + 34187² + 36502² + 59,501²

Sum of the squares of data points = 9,021,404,700

>> Then, we compute the average of the squares of all data points by dividing the sum of the squares of all data points by the number of data points:

Average of the squares
= Sum of the squares of data points ÷ number of data points
= 9,021,404,700 ÷ 13
Average of the squares = 693,954,207.69231
 
>> Finally, the standard deviation is the square root of the difference of the average of squares and the square of the average of the data points:

$\sigma = \sqrt{E(X^2) -(E(X))^2}$

where:

$\sigma = \text{standard deviation}
\\ E(X) = \text{average of all data points} = 22,150.62
\\ E(X^2) = \text{average of the squares of all data points} \approx 693,954,207.69231
$

So, the standard deviation is given by

$\sigma = \sqrt{E(X^2) -(E(X))^2}
\\ \sigma = \sqrt{693,954,207.69231 -(22,150.62)^2}
\\ \boxed{\sigma \approx 14,258.49}
$

Therefore, the standard deviation is 14,258.49.

3 0

3 years ago