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4 years ago

6. The Grand Theater has 13,451 seats. If 15,340 people need to be seated in the theater for a music concert, write and solve

Mathematics

2 answers:

Elena L [17]4 years ago

8 0

Hey There!

To find how many seats are needed to be added, you need to subtract 15,340 by 13,451. You need to find the difference between the seats you need and the seats you have. So...

15,340-13,451= 1,889

You need to add 1,889 more seats.

Hope This helped!

Godspeed,

SongBird

Akimi4 [234]4 years ago

8 0

Answer:

The required equation is 13451 + x = 15340,

1,889 seats are needed.

Step-by-step explanation:

Given,

Original number of seats = 13,451,

Also, the number of people who needed to be seated = 15,340,

Let x seats were added,

So, the new number of seats = 13451 + x

Thus, 15,340 will get the seat,

If total seats = 15340

⇒ 13451 + x = 15340

Which is the required equation,

Subtract 13451 on both sides,

We get,

x = 1889

Hence, 1889 seats are needed to accommodate all the people.

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Find an equation for those points P such that the distance from P to A(0, 1, 2) is equal to the distance from P to B(6, 4, 2). W

suter [353]

Answer: The required equation for points P is $4x+2y=17.$

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We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

$RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.$

Let the point P be represented by (x, y, z).

According to the given information, we have

$PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.$

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8 0

3 years ago

A book contains 400 pages. If their are 80 typing errors randomly distributed throughout the book, use the Poisson distribution

Nikitich [7]

Using the Poisson distribution to determine the probability that a page contains exactly 2 errors is 0.0163

<h3><u>Solution:</u></h3>

Given that, a book contains 400 pages.

There are 80 typing errors randomly distributed throughout the book,

We have to use the Poisson distribution to determine the probability that a page contains exactly 2 errors.

<em><u>The Poisson distribution formula is given as:</u></em>

$\text { Probability distribution }=e^{-\lambda} \frac{\lambda^{k}}{k !}$

Where, $\lambda$ is event rate of distribution. For observing k events.

$\text { Here rate of distribution } \lambda=\frac{\text { go mistakes }}{400 \text { pages }}=\frac{1}{5}$

And, k = 2 errors.

$\begin{array}{l}{\text { Then, } \mathrm{p}(2)=e^{-\frac{1}{5}} \times \frac{\frac{1}{5}}{2 !}} \\\\ {=2.7^{-\frac{1}{5}} \times \frac{\frac{1}{5^{2}}}{2 \times 1}} \\\\ {=\frac{1}{2.7^{\frac{1}{5}}} \times \frac{\frac{1}{25}}{2}}\end{array}$