Given: BD is a diameter m 1 = 100° m BC= 30° m ADB= 160 280 330
2 answers:
Answer with explanation:
Given
m∠1=100°
To Find:---m∠A D B
Solution
In Δ A OD
Represent the center of circle by O.
→ m∠1=100°
→OD=O A----------Radii of Circle
→∠ADO=∠D A O--------If opposite sides are equal angle opposite to them are equal.
In ΔA OD, Using Angle Sum property of Triangle
→∠ADO+∠D A O+∠A OD=180°
→2 ∠ADO+100° =180°-------------------[∠ADO=∠D A O]
→2∠ADO=180° -100°
→2∠ADO=80°
Dividing both sides by , 2 we get
⇒∠ADO=40°
⇒⇒⇒∠A DB=40°
≡⇒If you are asking about
Because Angle in a semicircle is Right Angle.Diameter B D divides the circle into two equal arc measure of each arc being 180 degree.
⇒⇒If you are asking about Angle made by Major arc ADB, then
Option B
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Answer:
B
Step-by-step explanation:
Given,
Dividend =
Divisor =
Step 1: First The dividend is and Divisor is
when divided first time the quotient will be
and remainder will be
Step: 2 Now the new dividend is and Divisor is
when divided the quotient will be
and remainder will be
Step: 3 Now the new dividend is and Divisor is
when divided the quotient will be
and remainder will be
Step: 4 Now the new dividend is and Divisor is
when divided the quotient will be
and remainder will be
Step: 5 Now the new dividend is and Divisor is
when divided the quotient will be
and remainder will be 0.
Hence When the polynomial is divided by
the answer or quotient will be equal to
and remainder will be 0.
So, you can do this one of two ways.
The first is knowing what the numbers in your equation represent:
For example: y=mx+b in this case "b" is 9. b is the y-value when x=0. So the first point on our graph is (0,9). Next we have to pick an xvalue to solve for another y-coordinate.
I chose x= -3. Plug x into the equation to get y.
y=3x+9
y=3(-3)+9
y=(-9)+9
y=0
So, our second point is (-3,0).
connect the points with a ruler to graph the line.
The first is knowing what the numbers in your equation represent:
For example: y=mx+b in this case "b" is 9. b is the y-value when x=0. So the first point on our graph is (0,9). Next we have to pick an xvalue to solve for another y-coordinate.
I chose x= -3. Plug x into the equation to get y.
y=3x+9
y=3(-3)+9
y=(-9)+9
y=0
So, our second point is (-3,0).
connect the points with a ruler to graph the line.