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Aloiza [94]
3 years ago
11

Solve: 3x - 7 - 2x + 5 = 6 A) -8 B) - 18 5 C) 4 D) 8

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

D) 8

Step-by-step explanation:

3x - 7 - 2x + 5 = 6

3x - 2x  = 6 + 7 - 5

  x   = 8

Note: 6 + 7 -5 =  13 -5 = 8

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Can someone help me with this question please?
Anna71 [15]

Answer:

  36 ft²

Step-by-step explanation:

If BE = 3√2 ft, then the diagonal BD is 6√2 ft. The area of the square (as with any rhombus) is half the product of the diagonals. Since both diagonals are the same length, the area of the square is ...

  area = 1/2·(6√2 ft)² = 36 ft²

The area of the square is 36 square feet.

_____

You may be expected to find the length of one side of the square using the Pythagorean theorem.

  AB² = AE² + EB² . . . . . = the area of the square

  AB² = (3√2 ft)² +(3√2 ft)² = 18 ft² + 18 ft²

  AB² = 36 ft² . . . . . . . . . the area of the square

8 0
3 years ago
Consider angle θ in Quadrant ll, where cos θ= -12/13. what's the value of sin θ​
Bas_tet [7]

Answer:

sinθ = 5/13

Step-by-step explanation:

cosθ​ = adjacent/hypotenuse (or you could think of it as x/r)

cosθ = -12/13

adjacent = -12

hypotenuse = 13

opposite = ?

To get the opposite, we use the Pythagorean theorem

hypotenuse^{2} = adjacent^{2}  + opposite^2

hypotenuse^{2} - adjacent^{2}  = opposite^2

\sqrt(hypotenuse^{2} - adjacent^{2})  = opposite

Now sub in the numbers:

\sqrt{(13^2 - (-12)^2)} = opposite

opposite = 5

Now sinθ = opposite/hypotenuse

so sinθ = 5/13

6 0
2 years ago
What additional information do you need to prove that ∆LMO ≅ ∆LNO by the HL Theorem? ∠NLO ≅ ∠MLO ∠MOL ≅ ∠NOL
FromTheMoon [43]
The hypotenuse leg theorem states that any two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.
The triangles ΔLNO and ΔLMO have the same leg Lo, therefore you need the equality of hypotenuses LM=LN.

5 0
3 years ago
Read 2 more answers
How to find the answer of :125% of _ is 625​
ololo11 [35]

Answer:

125% of 781.25 is 625

5 0
2 years ago
Read 2 more answers
Factor 2k^2 - k - 3<br> A: (2k-3)(k+1)<br> B: (k-1)(2k+3)<br> C: (2k-1)(k+3)<br> D: (k-3)(2k+1)
Art [367]

Answer:

A

Step-by-step explanation:

Given

2k² - k - 3

Consider the factors of the product of the k² term and the constant term which sum to give the coefficient of the k- term.

product = 2 × - 3 = - 6 and sum = - 1

The factors are + 2 and - 3

Use these factors to split the k- term

2k² + 2k - 3k - 3 ( factor the first/second and third/fourth terms )

= 2k(k + 1) - 3(k + 1) ← factor out (k + 1) from each term

= (2k - 3)(k + 1) → A

4 0
3 years ago
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