Answer:
if someone were to commit a crime and there were 3 leads and one piece of evidence, the 3 people would have to be extracted of some dna and so would the piece of evidence, and the person that matches the dna on the evidence would be tied to the crime
Answer:
If you did not follow the procedure as you should have.
Explanation:
You may have to repeat an experiment for several reasons. It can be because you need to be certain of the results so that you have to perform it several times. Or you need more precise results so that you can fine-tune the variables and repeat the experiment again.
The most common scenario where an experiment would be replicated would be in a situation where you did not follow the procedure that you have outlined exactly like you should have so that the results you got are not 100% reliable. In such a case, the experiment would need to be replicated for the correct results.
I hope this answer helps.
Answer:
Since the beginning of life of the first multicellular organisms, the preservation of a physiologic milieu for every cell in the organism has been a critical requirement. A particular range of osmolality of the body fluids is essential for the maintenance of cell volume. In humans the stability of electrolyte concentrations and their resulting osmolality in the body fluids is the consequence of complex interactions between cell membrane functions, hormonal control, thirst, and controlled kidney excretion of fluid and solutes. Knowledge of these mechanisms, of the biochemical principles of osmolality, and of the relevant situations occurring in disease is of importance to every physician. This comprehensive review summarizes the major facts on osmolality, its relation to electrolytes and other solutes, and its relevance in physiology and in disease states with a focus on dialysis-related considerations.
biotic- living things
abiotic- non living things
Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
