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4 years ago

Which unit could be used to measure the weight of a cat?

Mathematics

1 answer:

lesantik [10]4 years ago

8 0

Ummmmmmm pounds or grams

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In ΔJKL, k = 3.7 cm, ∠K=15° and ∠L=41°. Find the length of j, to the nearest 10th of a centimeter.

Alexandra [31]

Answer:

The length of side j is 11.85cm

Step-by-step explanation:

Given that

In triangle JKL,

$\angle k=15$

$\angle l=41$

Side k=LJ=3.7cm

To find side j=KL:

By using sine rule,

We can write as

$\frac{SinK}{LJ} = \frac{SinL}{JK} = \frac{SinJ}{KL} \\\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{SinJ}{KL}$

Using property of triangle,

$\angle k+\angle l+\angle j=180$

$15+41+\angle j=180$

$\angle j=124$

$\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{Sin124}{KL}\\\frac{Sin15}{3.7} = \frac{Sin124}{KL}\\KL=3.7\frac{Sin124}{Sin15}\\KL=3.7\frac{0.8290}{0.2588}\\KL=11.85cm$

Thus,

The length of side j is 11.85cm

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3 years ago

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3 years ago

Helpppp plss, which ones are growth or decay

vampirchik [111]

Answer:

Decay

Growth

Decay

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Step-by-step explanation:

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3 years ago

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a_sh-v [17]

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3 years ago

A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat

oksano4ka [1.4K]

Answer-

The insect population at the end of week 11 is 1730.

Solution-

A population of insects grows exponentially.

The general form of exponential function is,

$y=ab^x$

Where,

a, b are constants.

Putting the data given in the table, in the the equation in order to get the values of a, b

At (0, 20)

$\Rightarrow 20=ab^0$

$\Rightarrow a\cdot (1)=20$

$\Rightarrow a=20$

Now the exponential function becomes,

$y=20b^x$

At (1, 30)

$\Rightarrow 30=20b^1$

$\Rightarrow 20b=30$

$\Rightarrow b=\dfrac{30}{20}$

$\Rightarrow b=\dfrac{3}{2}$

Now the equation becomes,

$y=20(\frac{3}{2})^x$

For calculating the number of insects at the end of the 11th week, putting x=11, so

$y=20(\frac{3}{2})^{11}$

$=1729.95 \approx 1730$

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4 years ago

Read 2 more answers