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Dmitry_Shevchenko [17]
3 years ago
11

Astronomers sometimes use angle measures divided into degrees, minutes, and seconds. One degree is equal to 60 minutes, and one

minute is equal to 60 seconds. Suppose that ∠J and ∠K are complementary and that the measure of ∠J is 41 degrees, 38 minutes, 9 seconds. What is the measure of ∠K?
Pleaseee answer now!!!
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0

The measure of ∠K is 49 degrees 22 minutes 51 seconds.

<u>Step-by-step explanation:</u>

Given that ∠J and ∠K are complementary.

∠J = 41°38'9".

∠K = ?

When a sum of two angles result is 90°, then it is called as complementary angles.

Since ∠J and ∠K are complementary, then their sum is 90°.

∠J +∠K=90°.

∠K= 90° - ∠J.

=90°60'60" - 41°38'9".

=49°22'51".

∠K= 49 degrees 22 minutes 51 seconds.

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timama [110]

Answer:

Domain:— [ x ≥ -2, x ≤ -3 ]

Range:— [ y ≥ 0 ]

Step-by-step explanation:

You may use graphing calculator to draw a graph and examine the graph’s domain and range. However, I’ll explain further about the graph of quadratic in a surd.

First, factor the quadratic expression in the surd:—

\displaystyle \large{f(x)=\sqrt{(x+3)(x+2)}}

We can find the x-intercepts by letting f(x) = 0.

I’ll be separating in two parts — one for finding x-intercept and one for finding y-intercept.

__________________________________________________________

Finding x-intercepts

Let f(x) = 0.

\displaystyle \large{0=\sqrt{(x+3)(x+2)}}

Solve for x, square both sides:—

\displaystyle \large{0^2 = (\sqrt{(x+3)(x+2)})^2}\\\displaystyle \large{0=(x+3)(x+2)}

Simply solve a quadratic equation:—

\displaystyle \large{x=-3,-2}

Therefore, x-intercepts are:—

\displaystyle \large{\boxed{x=-3,-2}}

__________________________________________________________

Finding y-intercept

Let x = 0.

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Therefore, y-intercept is:—

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__________________________________________________________

However, I want you to focus on x-intercepts instead. We know that the square root only gives you a positive value. That means the range of function can only be y ≥ 0.

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