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3 years ago

18/15 into a mixed number

Mathematics

1 answer:

mamaluj [8]3 years ago

3 0

$\frac{18}{15} = \frac{18:3}{15:3} = \frac{6}{5} =1 \frac{1}{5}$

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John increased the amount of water he drinks every day from

victus00 [196]

% Increase = Increase/original number x 100
Let I represent increase

((58-32)/32) x 100 = I
58oz - 32oz = 26oz
26/32 x 100 = I
0.8125 x 100 = I
Increase = 81.25%

5 0

3 years ago

A mechanic charged $220.28 to repair a car. The price included charges for 3 hours of labor and $126.53 for parts. How much does

Assoli18 [71]

Answer:

$31.25

Step-by-step explanation:

Let's set up an equation.

$220. 28 - total

$126.53 - cost for parts

3 - # of hours

? - price per hour

3h + $126.53 = $220.28

Subtract $126.53 from both sides.

3h = $93.75

Divide by 3.

h = $31.25

The mechanic charges $31.25 per hour for labor.

Hope that helps.

6 0

3 years ago

Does anyone know the answer to this please help

Finger [1]

Answer:

Sin M= 16/34

Cos M= 30/34

Tan M= 16/30

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=

Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = $x^2 + y^2 +z^2 = 4^2$

$z^2 = 16 -x^2 -y^2$

$z = \sqrt{16-x^2-y^2}$

The partial derivatives of $Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}$

$Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}$

Similarly;

$Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}$

∴

$dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA$

$=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA$

$=\sqrt{ \dfrac{16}{16-x^2-y^2} }\ \ .dA$

$=\dfrac{4}{\sqrt{ 16-x^2-y^2} }\ \ .dA$

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to $\sqrt{12}$

dA = rdrdθ

∴

The surface area $S = \int \limits _R \int \ dS$

$= \int \limits _R\int \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA$

$= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \ \ rdrd \theta$

$= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr$

$= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}$

$= 8\pi ( - \sqrt{4} + \sqrt{16})$

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0

3 years ago

Hey can you please answer this question on 7th grade exponents? thank you! boo

Ket [755]

A. 75 x 0.0016= .12 Has a value between 0 and 1

B. 3^5 / 3^-6 = 177147 Does not a value between 0 and 1

C. 1/4^3 x 1/4^2 = about 0.0009 Has a value between 0 and 1

D. -7^5 / -7^7 = about 0.02 Has a value between 0 and 1

8 0

4 years ago

Read 2 more answers