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3 years ago

How do you work out y?

Mathematics

2 answers:

frutty [35]3 years ago

6 0

Answer:

Step-by-step explanation:

Write the sides as proportions:

$\frac{30}{18}=\frac{40}{y}$

and cross multiply to get

30y = 720 so

y = 24

yan [13]3 years ago

5 0

You could cross multiply and the answer will be y=24 hope this helps:)

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I need find volumen i need help

ValentinkaMS [17]

Answer:

it's 512

Step-by-step explanation:

5 0

3 years ago

What forms of the following equation in?<br><br> y+5=7(x−3)

skelet666 [1.2K]

I think it would be -26

3 0

2 years ago

Read 2 more answers

The triangle has size with the lengths of 3 cm 13 cm and 14 cm Is it a right triangle?

WITCHER [35]

Answer:

No, it is not a right triangle

Step-by-step explanation:

Let H = 14 cm

B = 3 cm

P = 13 cm

According to pythagoras theorem:

H^2 = P^2 + B^2

14^2 = 13^2 + 3^2

196 = 169 + 9

196 is not equal to 178

Hence, it is not a right triangle

6 0

3 years ago

An auto shop charges a customer an equal amount for each new tire purchased plus an additional fee for an oil change.

Nitella [24]

The cost per unit of the auto shop function is the slope of the function

87 represents the slope and the cost per tire purchased

The function is given as:

$\mathbf{C(t) = 87t + 32}$

A linear function is represented as:

$\mathbf{C(t) = mt + b}$

Where:

m represents the slope or the unit rate.

So, by comparison:

$\mathbf{m = 87}$

This means that 87 represents the slope and the cost per tire purchased

Read more about slopes at:

brainly.com/question/18576224

6 0

3 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago