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2 years ago

What technology allows data to be stored in one place and be retrieved by many systems?

Computers and Technology

1 answer:

Mice21 [21]2 years ago

4 0

ICloud is one of the many different tech options.
Hope I helped,
Ms. Weasley

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network consisting of computers and other devices that are eithrr fully or partially connected to each other

tekilochka [14]

The answer is a Mesh topology. This method connects every device to each other device in the network. A wired full-mesh topology is not as common as it is impractical and highly expensive. A partial mesh topology offers redundancy if one of the connections goes down and usually uses a connecting medium such as a router to eliminate cables and expensive PCI NIC's.

8 0

2 years ago

Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and evens (like the 10 or 90)

yanalaym [24]

Answer:

The solution in python.

Output:

print("0 is not a valid interstate highway number")

Explanation:

h = int(input("enter highway number: ")) #take highway number

if(h>=1 and h<=99): #for primary highway

if(h%2==0):

print("I-%d is primary, going east/west" %h) #for even highway number

else:

print("I-%d is primary, going north/south" %h) #for odd highway number

elif(h>=100 and h<=999): #for auxiliary highway

aux=str(h) #convert into string for fetch the rightmost number

l=len(aux) #find the length

val = aux[l-2]+aux[l-1] #assign value of rightmost two number

h = int(val) #convert into integer

if(h%2==0):

print("I-"+aux+" is auxiliary,"+"serving I-%d, going east/west" %h)

else:

print("I-"+aux+" is auxiliary,"+"serving I-%d, going north/south" %h)

elif(h==0):#for 0 highway number

print("0 is not a valid interstate highway number")

else:

pass

7 0

3 years ago

Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur

sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

for ip in range(octet_start, octet_end):

forth_octet = forth_octet + 1

if forth_octet > 255:

forth_octet = (forth_octet % 255) - 1

third_octet = third_octet + 1

if third_octet > 255:

third_octet = (third_octet % 255) - 1

second_octet = second_octet + 1

if second_octet > 255:

second_octet = (second_octet % 255) - 1

first_octet = first_octet + 1

if first_octet > 255:

print("No more available IP!")

break

print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0

3 years ago

Which of the following are good backup methods you can use to protect important files and folders from loss in the case of a har

grigory [225]

Answer:A,B, and D

Explanation:

6 0

2 years ago

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HELP URGENTLY!!!!!

Ganezh [65]

Which field TCP header is not typically used in modern networks

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3 years ago