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Kruka [31]
3 years ago
14

An element with a mass of 740 grams decays by 28.4% per minute. To the nearest minute, how long will it be until there are 30 gr

ams of the element remaining?
Mathematics
1 answer:
Genrish500 [490]3 years ago
7 0

Answer:t=9.6 minutes

Step-by-step explanation:

Given

mass of element is A_o=740\ gm

Decay rate r=28.4\%\ \text{per minute}

and we know

Amount of exponential decay is given by

A=A_o[1-r]^t

Where A_0=\text{Initial amount}

\text{A=Accumulated amount}

\text{r=rate}

\text{t=time}

Substituting values we get

\Rightarrow 30=740[1-0.284]^t

\Rightarrow \dfrac{30}{740}=0.716^t

\Rightarrow 0.0405=0.716^t

taking log both sides we get

\Rightarrow\ \ln (0.0405)=t\times \ln (0.716)

\Rightarrow t=\dfrac{\ln (0.0405)}{\ln (0.716)}

\Rightarrow t=9.598\approx 9.6\ \text{minutes}

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