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Kobotan [32]
3 years ago
15

Find the area of the shaded polygons:

Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

I think the last one is maybe ten, maybe

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Carlos tiene una produccion semanal de 500kg de papas negras y 600kg de batatas al cabo de 12 semanas de ¿cuanto sera la producc
REY [17]

Step-by-step explanation:

<u />

<u>1.Producción semanal de papas negras</u>:500kg x 12 semanas=6.000kg por 12 semanas de papa negra

<u>2.Producción semanal de batatas:</u> 600 kg x 12 semanas=7.200kg por 12 semanas de batata

<u>3.Producción total</u>: Para obtenerla producción total sumamos el total producido por las 12 semanas entre papa negra y batata.Entonces tenemos:

6.000kg de papa negra + 7.200 kg de batata=<u>13.200 kg </u>de producido total  entre papa negra y batata por 12 semanas

4 0
3 years ago
Find the greatest common factor of 16 and 33.
Luden [163]

Answer:

1

Step-by-step explanation:

The greatest common factor of 16 and 33 is 1.

16 x 1 = 16

16 x 2 = 32

16 x 3 = 48

33 x 1 = 33

33 x 2 = 66

33 x 3 = 99

3 0
3 years ago
How do I solve <br> 2(6x-1)+2(2x+5)=120
Tomtit [17]

2(6x-1)+2(2x+5)=120

12x-2+4x+10=120

16x+8=120 |-8

16x=112 |/16

x=112/16

x=7

7 0
3 years ago
Round-trip bus fare is $2. Justin rides the bus 5 days a weeks to work and 2 nights a week to school. He can buy a pass at schoo
Ivan

Answer:

It would be cheaper to use the round-trip bus fare.

5 0
3 years ago
Find the sum of a finite geometric series. The Smiths spent $2,000 on clothes in a particular year. If they increase the amount
boyakko [2]

\bf \stackrel{\textit{first year}}{2000}~~,~~\stackrel{\textit{second year}}{2000+\stackrel{\textit{10\% of 2000}}{\frac{2000}{10}}}\implies 2200

now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus \bf 110\%\implies \cfrac{110}{100}\implies 1.1.

so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1}  \right)\\\\\\S_4=2000(4.641)\implies S_4=9282

7 0
3 years ago
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