Answer:
<h2> 105 tickets</h2>
Step-by-step explanation:
To solve this problem we need to model an equation to represent the situation first.
the goal is to archive $7500 in the even, bearing in mind that there is a cost of $375 fee for rent, we need to put this amount into consideration
let the number of tickets be x
so
75x-375>=7500--------1
Equation 1 above is a good model for the equation
we can now solve for x to determine the number of tickets to be sold to archive the aim
75x-375>=7500--------1
75x>=7500+375
75x>=7875
divide both sides by 75 we have
x>=7875/75
x>=105 tickets
so they must sell a total of 105 tickets and above to meet the target of $7500 with the rent inclusive
About 20 cars. Easiest way to figure it out is do 231$ divides by 12$ and get 19.25, so 20.
6^7
-----
6^5
===
answer would be
6^2
19/25 = x/100
Cross multiply:
1,900
Divide 1,900 by 25
Equals 76
Subtract 76 from 100
Answer: 24% change
I hope this helps!