1) √3 √7 = √21
2) √5 √245 = √5 √5 * 49 = √5 * 7√5 = 7 √5 * 5 = 7 √25 = 7 * 5 = 35
3) √77 ÷ √11 = as is. can't be simplified.
4) (√59)² = 59 ; the square root was cancelled by squared.
5) 3√6 x 8√7 = 3 * 8 √6 * 7 = 24 √42
6) 5√3 x 6 √3 = 5 * 6 √3 * 3 = 30 √9 = 30 * 3 = 90
7) 40√30 ÷ 5√3 = (40 / 5) * (√30 /√3) = 8 * ((√3 *10) / √3) = 8 √10
8) (6√5)² = 6² * √5² = 36 * 5 = 180
Answer:
1600 integers
Step-by-step explanation:
Since we have a four digit number, there are four digit placements.
For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.
For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.
For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers
A = hw
Replace h with 4h
Replace w with 4w
A = (4w)(4h)
= 16hw
The area becomes 16 times larger.
Have an awesome day! :)
Answer:
5 – 6x = 8x + 17
⇔ 5 - 17 = 8x + 6x
⇔ -12 = 14x
⇔ x = -6/7
Step-by-step explanation:
