Question

4. What are the zeros of the polynomial function y= 2x2-3x+1?

Answer 1

Answer:

A

Step-by-step explanation:

Given

y = 2x² - 3x + 1

To find the zeros let y = 0, that is

2x² - 3x + 1 = 0

Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × 1 = 2 and sum = - 3

The factors are - 2 and - 1

Use these factors to split the x- term

2x² - 2x - x + 1 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) - 1(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x - 1) = 0

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = $\frac{1}{2}$

x - 1 = 0 ⇒ x = 1