Answer:
<h2>9/5</h2>
Step-by-step explanation:
<h3>4 1/5 × 3/7</h3><h3 /><h3>•change 4 1/5 into an <u>improper fraction</u></h3><h3 /><h3>21/5 × 3/7</h3><h3 /><h3>= 63/35</h3><h3 /><h3>= 9/5 </h3>
Answer:
11 hours she worked at the grocery store
Step-by-step explanation:
assuming,
the number of hours worked at tutoring = x
the number of hours worked at grocery store = y
which means,
the amount she made at tutoring = x* $15
the amount she made at grocery store = y*$9
we have 2 equations
<em>total number of hours</em>
1) x+y= 15
<em>total amount she earned</em>
2) x* $15+ y* $9= $159
From equation 1
x+y= 15
x=15-y
<em>we replace this x value in equation 2</em>
x* $15+ y* $9= $159
(15-y)* $15+ y* $9= $159
(15*15)- 15y+9y=159
225-6y=159
225-159=6y
66=6y
66/6=y
<u>11=y</u> <em>the number of hours she worked at grocery store. </em>
<em>we place y=11 in our derived x equation</em>
x=15-y
x=15-11
<u><em>x=4 </em></u><em>the number of hours she worked at tutoring. </em>
2
+
4
5
=
−
1
4
x
2
+
45
=
−
14
x
x2+45=−14x
2
+
4
5
−
−
1
4
=
0
Answer:
x = 
Step-by-step explanation:
x^2 + 8^2 = 9
Simplify the 8^2
x^2 + 64 = 9
Subtract 64 from both sides
x^2 = -55
Take the square root from both sides
x = +/- 
Simplify
x =
Hope this helps!
If you want to check if (1,2) is a solution to the system, you have to plug the x and y values back into both equations. If they work for one equation, but not the other, than the coordinates are not a solution to the system.
3(1) - 4(2) = -5
3 - 8 = -5
-5 = -5
2 = 4(1) - 2
2 = 4 - 2
2 = 2
Since both of these checks are true, then (1,2) is a solution to the system.
