Using the Empirical Rule and the Central Limit Theorem, we have that:
- About 68% of the sample mean fall with in the intervals $1.64 and $1.82.
- About 99.7% of the sample mean fall with in the intervals $1.46 and $2.
<h3>What does the Empirical Rule state?</h3>
It states that, for a normally distributed random variable:
- Approximately 68% of the measures are within 1 standard deviation of the mean.
- Approximately 95% of the measures are within 2 standard deviations of the mean.
- Approximately 99.7% of the measures are within 3 standard deviations of the mean.
<h3>What does the Central Limit Theorem state?</h3>
By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem, the standard deviation of the distribution of sample means is:

68% of the means are within 1 standard deviation of the mean, hence the bounds are:
99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:
More can be learned about the Empirical Rule at brainly.com/question/24537145
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For C highest to lowest
4/5, 3/4, 7/10, 1/2
For D
3/4, 17/24, 2/3, 7/12, 1/6
D. Worm! Viruses, worms, rasonware, Trojans, bonets, and adware are also some examples!
X will equal 8 and y would equal 3
Answer:
t = 13.2 s
Step-by-step explanation:
Given that,
An athlete ran the 100 meter sprint in 13.245 seconds. We need to round off the time to the nearest tenth.
Here, t = 13.245 s
In order to round off to the nearest tenth, thousandths place and hundredth place gets eliminated.
So, t = 13.2 s
So, time is 13.2 seconds.