1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mr Goodwill [35]
3 years ago
14

A water strider bug is supported on the surface of a pond by surface tension acting along the interface between the water and th

e bug’s legs. Assume the bug weighs 10−4 N and the surface tension force acts vertically upward. Determine the minimum length of the interface needed to support the bug
Physics
1 answer:
Alik [6]3 years ago
4 0

Answer:

minimum interface length = 1.36 mm

Explanation:

given data

weight of the bug = 10^{-4} N

solution

we will apply here Surface Tension formula that is

Surface Tension ,σ = Force ÷ length      ........................1

and we consider here surface tension for water is 7.34 × 10^{-2} N/m

so that here minimum interface length needed to support the bug is

minimum interface length = Force ÷ σ

minimum interface length = 10^{-4}  ÷ 7.34 × 10^{-2}

minimum interface length = 1.36 mm

                                                                                     

                                                                                     

You might be interested in
monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central
hjlf

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

<h3>How to find Wavelength of the light?</h3>

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

To learn more about Wavelength of the light refer to:

brainly.com/question/15413360

#SPJ4

5 0
1 year ago
Which aspect of relativity makes faster-than-light travel theoretically possible?
koban [17]

Answer:

The ability of space-time to move

Explanation:

6 0
3 years ago
1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential
cupoosta [38]
<h3>Answer:</h3>

\displaystyle U_s = 0.6 \ J

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Physics</u>

<u>Energy</u>

Elastic Potential Energy: \displaystyle U_s = \frac{1}{2} k \triangle x^2

  • U is energy (in J)
  • k is spring constant (in N/m)
  • Δx is displacement from equilibrium (in m)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

k  = 7.50 N/m

Δx = 0.40 m

<u>Step 2: Find Potential Energy</u>

  1. Substitute in variables [Elastic Potential Energy]:                                        \displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2
  2. Evaluate exponents:                                                                                      \displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)
  3. Multiply:                                                                                                           \displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)
  4. Multiply:                                                                                                           \displaystyle U_s = 0.6 \ J
6 0
3 years ago
Which is a physical property that can be used to tell one substance from another?
siniylev [52]

Should be B. Density.

3 0
3 years ago
Read 2 more answers
The substance that a wave moves through is called a __________.
klio [65]
The substance that a wave moves through is called a _medium_
4 0
4 years ago
Read 2 more answers
Other questions:
  • In an experiment, a researcher can make claims about causation
    5·1 answer
  • Which one of the following states of matter has no definite shape but does have a fixed volume A. Liquid B. Element C. Gas D. So
    7·2 answers
  • Why is science literacy important?
    8·1 answer
  • Need help on this please
    13·1 answer
  • A body moves in circle cover half of revolution in 10 sec its linear distance became 10m along circumference of circle than its
    9·1 answer
  • Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 × 108 m. Find th
    8·1 answer
  • What is fast carbon and what is slow carbon
    15·1 answer
  • If a 2kg ball has and initial velocity of
    10·1 answer
  • Find the current is in the circuit? ​
    9·1 answer
  • Make a conclusion on the relationship of mass to the rate of the change of motion of the balloon at a constant force.​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!