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Llana [10]
4 years ago
7

The substance that a wave moves through is called a __________.

Physics
2 answers:
tangare [24]4 years ago
6 0
- - A medium is the substance in which a wave moves through. This is because the medium in a wave makes it possible to generate and transfer energy from one location to another, which is why the waves are able to go out, than in. 

klio [65]4 years ago
4 0
The substance that a wave moves through is called a _medium_
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A boat crossing a 153.0 m wide river is directed so that it will cross the river as quickly as possible. The boat has a speed of
Lynna [10]

We have the relation

\vec v_{B \mid E} = \vec v_{B \mid R} + \vec v_{R \mid E}

where v_{A \mid B} denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.

We're given speeds

v_{B \mid R} = 5.10 \dfrac{\rm m}{\rm s}

v_{R \mid E} = 3.70 \dfrac{\rm m}{\rm s}

Let's assume the river flows South-to-North, so that

\vec v_{R \mid E} = v_{R \mid E} \, \vec\jmath

and let -90^\circ < \theta < 90^\circ be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that

\vec v_{B \mid R} = v_{B \mid R} \left(\cos(\theta) \,\vec\imath + \sin(\theta) \, \vec\jmath\right)

Then the velocity of the boat relative to the Earth is

\vec v_{B\mid E} = v_{B \mid R} \cos(\theta) \, \vec\imath + \left(v_{B \mid R} \sin(\theta) + v_{R \mid E}\right) \,\vec\jmath

The crossing is 153.0 m wide, so that for some time t we have

153.0\,\mathrm m = v_{B\mid R} \cos(\theta) t \implies t = \dfrac{153.0\,\rm m}{\left(5.10\frac{\rm m}{\rm s}\right) \cos(\theta)} = 30.0 \sec(\theta) \, \mathrm s

which is minimized when \theta=0^\circ so the crossing takes the minimum 30.0 s when the boat is pointing due East.

It follows that

\vec v_{B \mid E} = v_{B \mid R} \,\vec\imath + \vec v_{R \mid E} \,\vec\jmath \\\\ \implies v_{B \mid E} = \sqrt{\left(5.10\dfrac{\rm m}{\rm s}\right)^2 + \left(3.70\dfrac{\rm m}{\rm s}\right)^2} \approx 6.30 \dfrac{\rm m}{\rm s}

The boat's position \vec x at time t is

\vec x = \vec v_{B\mid E} t

so that after 30.0 s, the boat's final position on the other side of the river is

\vec x(30.0\,\mathrm s) = (153\,\mathrm m) \,\vec\imath + (111\,\mathrm m)\,\vec\jmath

and the boat would have traveled a total distance of

\|\vec x(30.0\,\mathrm s)\| = \sqrt{(153\,\mathrm m)^2 + (111\,\mathrm m)^2} \approx \boxed{189\,\mathrm m}

3 0
2 years ago
The formula CO2 is an example of
galina1969 [7]
Ionic Compound is the answer

4 0
3 years ago
01:28:29
Novosadov [1.4K]

Answer:

an inverse relationship

7 0
3 years ago
The current in the wires of a circuit is 120.0 milliAmps. If the voltage impressed across the ends of the circuit were doubled (
skad [1K]

Answer:

Its new current will be 240.0milliAmps

Explanation:

According to ohms law,

V = IR

V is the supply voltage in a circuit

I is the current

R is the resistance

If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:

V1 = 120R1

R1 = V1/120...(1)

If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),

V2 = 2V1

V2 = IR2

2V1 = IR2

R2 = 2V1/I ... (2)

Since there are no changes in resistance

R1 = R2

Equating 1 and 2, we have:

V1/120 = 2V1/I

1/120 = 2/I

Cross multiplying

I = 2×120

I = 240milliAmps

7 0
3 years ago
How fast should a girl of 35 kg run so that her kinetic energy becomes 700J<br> of?
Kipish [7]
V^2 = 700J/0.5*35kg

V = square root of 40

v = 6.324 m/s
6 0
3 years ago
Read 2 more answers
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