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Sunny_sXe [5.5K]
2 years ago
7

2) Find f-1(x) where f(x) = 3x/x+4

Mathematics
1 answer:
Strike441 [17]2 years ago
4 0
The inverse would be 4x/3-x
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Please help me please final exam
Ann [662]

Answer:

360

Step-by-step explanation:

8 0
2 years ago
Indicate the equation of the given line in standard form.
Lorico [155]
We have that
<span>triangle ABC
where
A(-5, 5), B(1, 1), and C(3, 4) are the vertices

using a graph tool
see the attached figure

the hypotenuse is the segment AC

find the equation of the line AC
</span>A(-5, 5) C(3, 4) 
<span>
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=</span>(4-5)/(3+5)-----> m=-1/8

step 2
with C(3,4) and m=-1/8
find the equation of a line
y-y1=m*(x-x1)-----> y-4=(-1/8)*(x-3)----> y=(-1/8)*x+(3/8)+4
y=(-1/8)*x+(3/8)+4----> multiply by 8----> 8y=-x+3+32
8y=-x+35
the standard form is Ax+By=C
so
x+8y=35
A=1
B=8
C=35

the answer is
x+8y=35


7 0
3 years ago
A first year student deposits $250 into a savings account at the Owl Credit Union at Dundalk High School paying an annual intere
Brums [2.3K]
250 + 4 (4x250) = 500
3 0
3 years ago
Help me please (look the picture)
umka2103 [35]
You add 1 to the numerator each time
4 0
3 years ago
Help me please asap I need to know fully how to solve this problem
vivado [14]
Consider the absolute value, because we only worry about the quadrant later.

\text{Consider: } sin(A) = |-\frac{\sqrt{3}}{4}|
sin(A) = \frac{\sqrt{3}}{4}

Thus, we know that the hypotenuse has a length of 4 units, and the side opposite the angle, A is √3, because this is the nature of the sine function in relation to its triangular component.

The missing side can be found using Pythagoras' Theorem:
4² - (√3)² = x²
16 - 3 = x²
13 = x²
x = √13

\therefore tan(A) = \pm \sqrt{\frac{3}{13}}

Since angle A is in the third quadrant, the tangent function will produce a positive angle.

tan(A) = \sqrt{\frac{3}{13}}
\text{Rationalise the denominator: } \frac{\sqrt{3}}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}

tan(A) = \frac{\sqrt{39}}{13}
7 0
3 years ago
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