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Romashka-Z-Leto [24]
3 years ago
15

What is the answer to 4/5 - 3/4?

Mathematics
2 answers:
Lorico [155]3 years ago
8 0

Answer: 1/20

Step-by-step explanation:

In this question we will use LCM(least common multiple)

4/5-3/4

16-15/20

1/20

azamat3 years ago
7 0

Answer: 1/20

Step-by-step explanation:

you need to find a common denominator (least common multiple of both denominators)

4/5 - 3/4

16/20 - 15/20

1/20

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(495+5500) [one year] x 2 [two years] = $11,990

At the end of 2 years, Aldo will owe $11,990.
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3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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Step-by-step explanation:

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