When multiplying 0.9 X 4 you must turn the 4 into a 4.0 and then line up the decimal points

Suppose that $1,000 is deposited into an account that yields

Lana71 [14]

ANSWER : $1,215.51

P= Principal = $1000
R= rate = 5% = 0.05
N= number or periods in 1 year (1 time pre year)
T= time expressed in years = 4 years

A= P (1 + r/n) nxt
= 1,000 (1+ 0.05/1) 1x4
= 1,215.51

6 0

3 years ago

Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete

Helga [31]

Answer:

Becky, because her justification for the second statement should be "definition of supplementary angles" rather than "angle addition postulate."

Step-by-step explanation:

Becky completed the proof incorrectly because her justification for the second statement is not totally correct.

Angle addition postulate does not really apply here, as the sum of 2 angles may not give you exactly 180°.

However, the second statement, m<AKG + m<GKB = 180° and m<GKB + m<HKB = 180°, can be justified by the "Definition of Supplementary Angles".

The sum of supplementary angles = 180°.

Therefore, Becky completed the proof incorrectly.

6 0

3 years ago

If a seamstress is paid 7.85 per hour and works 18.75 hours in one week how much is she paid for that week

umka21 [38]

$18.75 hours at $7.85 pet hour is exactly 1471875, moving the decimal 4 places to the left and round to the nearest penny is
$147.1875 Or $147.19

4 0

3 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

3 years ago

How to convert 5/16 into a decimal

REY [17]

Answer:

Divide 5 by 16 and that’s 0.3125 round to 0.31

6 0

2 years ago

Read 2 more answers