Bobby. If you find the common denominator here which is 12 then Mina has 4/12 red pencils, bobby has 8/12 red pencils, and julia has 6/12 repent ils. Therefore bobby has the most red pencils.
Given:
First term of an arithmetic sequence is 2.
Sum of first 15 terms = 292.5
To find:
The common difference.
Solution:
We have,
First term: 
Sum of first 15 terms: 
The formula of sum of first n terms of an AP is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where, a is first term and d is common difference.
Putting , n=15 and a=2 in the above formula, we get
![292.5=\dfrac{15}{2}[2(2)+(15-1)d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B2%282%29%2B%2815-1%29d%5D)
![292.5=\dfrac{15}{2}[4+14d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B4%2B14d%5D)
![292.5=15[2+7d]](https://tex.z-dn.net/?f=292.5%3D15%5B2%2B7d%5D)
Divide both sides by 15.
Dividing both sides by 7, we get
Therefore, the common difference is 2.5.
Answer:
B
Step-by-step explanation:
so 8(2)=16=5x-4
5x=20
x=4
so B
This looks like common core which is never straight forward.It seems as though they are asking for the perimeter and not area,since they used feet for the distance around instead of sq.ft.
Let the three consecutive integers be x , x+1 ,x+2
Given, sum of three consecutive integers = -126
x +x+1+ x+2 = -126
3x +3 = -126
3x = -126 -3
3x = -129
x = -129/3
x = - 43
x +1 = -42
x +2 = -41
