They function as catalysts, they transport and store other molecules such as oxygen, they provide mechanical support and immune protection, they generate movement, they transmit nerve impulses, and they control growth and differentiation
Answer:
to the right (products side)
Explanation:
The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:
a A + b B → c C + d D
The equilibrium constant expression is:
![K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%5BD%5D%5E%7Bd%7D%20%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%20%7D)
A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).
Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.
Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.
Answer:
590 g CaCl₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
5.3 mol CaCl₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol
<u>Step 3: Convert</u>
<u />
= 588.194 g CaCl₂
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
588.194 g CaCl₂ ≈ 590 g CaCl₂
Answer:
ΔGº = --29 kJ
Explanation:
The equation to use is ΔGº = -nFEºcell
where n is the number of mole of electrons exchanged in the redox equation
F is Faraday´s constant 96485 C/mole
Eº cell potential
Ni²⁺(aq) + 2e⁻ ⇒ Ni (s) Eºred = -0.25 V
Cd(s) ⇒ Cd²⁺ + 2e⁻ Eºox = +0.40 V
Eºcell = 0.40 V -0.25 V = 0.15 V
ΔGº = - 2 mole x 96485 C/mol x 0.15 V = -2.9 x 10⁴J = -29 kJ
(remember 1 Coulomb x 1 Volt = 1 Joule)