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Rudik [331]
3 years ago
13

Suppose a teaspoon of magnesium filings and a teaspoon of powdered sulfur are placed together in a metal beaker. Would this cons

titute a mixture or a pure substance?
Chemistry
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

Mixture

Explanation:

A mixture is made up of the two or more substances which are different and are physically combined. It is physical combination in which identities of each substance are retained.

Pure substances contain only one kind of the particle.

<u>When the teaspoon of the magnesium filings and the teaspoon of the powdered sulfur are together placed in the metal beaker, the constitute is mixture because it contains 2 substances which are physically mixed and both magnesium and sulfur show their properties individually.</u>

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Which is a function of a protein marcomolecule
Nutka1998 [239]
They function as catalysts, they transport and store other molecules such as oxygen, they provide mechanical support and immune protection, they generate movement, they transmit nerve impulses, and they control growth and differentiation
5 0
3 years ago
Read 2 more answers
The position of the equilibrium for a system where K = 6.4 × 10 9 can be described as being favoring ________________
geniusboy [140]

Answer:

to the right (products side)

Explanation:

The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:

a A + b B → c C + d D

The equilibrium constant expression is:

K = \frac{[C]^{c} [D]^{d}  }{[A]^{a} [B]^{b}  }

A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).

Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.

Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.

5 0
3 years ago
Determine whether the following pairs of elements can form ionic compounds
lapo4ka [179]

Answer:

Oxygen and Magnesium.

7 0
3 years ago
2. What is the mass of 5.3 moles of CaCl2?
Tanya [424]

Answer:

590 g CaCl₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

5.3 mol CaCl₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol

<u>Step 3: Convert</u>

<u />5.3 \ mol \ CaCl_2(\frac{110.98 \ g \ CaCl_2}{1 \ mol \ CaCl_2} ) = 588.194 g CaCl₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

588.194 g CaCl₂ ≈ 590 g CaCl₂

5 0
3 years ago
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Ni2 (aq) Cd(s) Ni(s) Cd2
Contact [7]

Answer:

ΔGº = --29 kJ

Explanation:

The equation to use is ΔGº = -nFEºcell

where n is the number of mole of electrons exchanged in the redox equation

           F is Faraday´s constant 96485 C/mole

           Eº  cell potential

Ni²⁺(aq) + 2e⁻    ⇒  Ni (s)    Eºred = -0.25 V

Cd(s)  ⇒  Cd²⁺ + 2e⁻           Eºox   = +0.40 V

Eºcell = 0.40 V -0.25 V = 0.15 V

ΔGº = - 2 mole x 96485 C/mol x 0.15 V =  -2.9 x 10⁴J = -29 kJ

(remember 1 Coulomb x 1 Volt = 1 Joule)

8 0
4 years ago
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