<span>The molar mass is 169.09
304.3g/169.09g = 1.799mol which rounds to 1.800 mol</span>
Answer:
solubility of X in water at 17.0
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0
can be calculated using the information given.
Let's assume solubility of X in water at 17.0
is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y =
= 0.11
Hence solubility of X in water at 17.0
is 0.11 g/mL.
Answer:
The density of this liquid is 0.320 kg/L
Explanation:
Given:
Volume of the Liquid = 0.820 L
Mass of the liquid = 2.56 kg.
To Find:
The density of the liquid in kg/L
Solution:
Density is the mass occupied by the substance in unit volume. This density is essential determining whether the substance floats or sinks. Greek letter(rho) is used to denote density
The equation of for density is


where m is the mass
v is the volume
On substituting the given values


Answer:
0.0063 mol
Explanation:
Step 1: Write the balanced combustion equation
C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(g)
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₈H₁₈ to CO₂ is 1:8.
Step 3: Calculate the number of moles of C₈H₁₈ needed to produce 0.050 moles of CO₂
0.050 mol CO₂ × 1 mol C₈H₁₈/8 mol CO₂ = 0.0063 mol C₈H₁₈
The answer is 5. An acetyl group (comprising two C atoms) is
divided off the original fatty acyl-SCoA with each recurrence of the
beta-oxidation spiral. So, the first repetition of the beta-oxidation produces
one acetyl-SCoA molecule and a fatty acyl-SCoA molecule that is two carbon
atoms smaller than the initial fatty acyl-SCoA. There will be five acetyl-SCoA
molecules made by the fifth repetition.