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n200080 [17]
4 years ago
10

Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Ni2 (aq) Cd(s) Ni(s) Cd2

(aq) Answer: -29.529 kJ K for this reaction would be than one.
Chemistry
1 answer:
Contact [7]4 years ago
8 0

Answer:

ΔGº = --29 kJ

Explanation:

The equation to use is ΔGº = -nFEºcell

where n is the number of mole of electrons exchanged in the redox equation

           F is Faraday´s constant 96485 C/mole

           Eº  cell potential

Ni²⁺(aq) + 2e⁻    ⇒  Ni (s)    Eºred = -0.25 V

Cd(s)  ⇒  Cd²⁺ + 2e⁻           Eºox   = +0.40 V

Eºcell = 0.40 V -0.25 V = 0.15 V

ΔGº = - 2 mole x 96485 C/mol x 0.15 V =  -2.9 x 10⁴J = -29 kJ

(remember 1 Coulomb x 1 Volt = 1 Joule)

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8 0
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Determine the enthalpy change for the decomposition of calcium carbonate. CaCO3 (s) --> CaO (s) + CO2 (g) given the thermoche
Gnesinka [82]

Answer : The enthalpy change for the decomposition of calcium carbonate is, 178.1 kJ/mol

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l)     \Delta H_1=65.02kJ/mol

(2) Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)    \Delta H_2=-113.8kJ/mol

(3) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_3=-393.5kJ/mol

(4) 2Ca(s)+O_2(g)\rightarrow 2CaO(s)    \Delta H_4=-1270.2kJ/mol

Now we are reversing reaction 1 and then adding reaction 1 and 2, we get :

(1) Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l)     \Delta H_1=65.02kJ/mol

(2) CaCO_3(s)+H_2O(l)\rightarrow Ca(OH)_2(s)+CO_2(g)    \Delta H_2=113.8kJ/mol

The expression for enthalpy of change will be,

\Delta H=\Delta H_1+\Delta H_2

\Delta H=(65.02)+(113.08)

\Delta H=178.1kJ/mol

Thus, the enthalpy change for the decomposition of calcium carbonate is, 178.1 kJ/mol

7 0
4 years ago
Calculate the concentration of so42− ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal pl
dimulka [17.4K]
<span>Answer: 0.00649M


The question is incomplete,
</span>

<span>You are told that the first ionization of the sulfuric acid is complete and the second ionization of the sulfuric acid has a constant Ka₂ = 0.012
</span>
<span>
With that you can solve the question following these steps"
</span>

<span>1) First ionization:
</span>
<span>
H₂SO₄(aq) --> H⁺ (aq) + HSO₄⁻ (aq)


Under the fully ionization assumption the concentration of HSO4- is the same of the acid = 0.01 M


2) Second ionization
</span>

<span>HSO₄⁻ (aq) ⇄ H⁺ + SO₄²⁻ with a Ka₂ = 0.012
</span>

<span>Do the mass balance:
</span>


<span><span>        HSO₄⁻ (aq)        H⁺        SO₄²⁻</span>
</span>
<span /><span /><span>        0.01 M  - x          x            x


</span><span>Ka₂ = [H⁺] [SO₄²⁻] / [HSO₄⁻]</span>
<span /><span>
=> Ka₂ = (x²) / (0.01 - x) = 0.012
</span><span />

<span>3) Solve the equation:


</span><span>x² = 0.012(0.01 - x) = 0.00012 - 0.012x</span>
<span /><span>
x² + 0.012x - 0.0012 = 0
</span><span />

<span>Using the quadratic formula: x = 0.00649
</span><span />

<span>So, the requested concentratioN is [SO₄²⁻] = 0.00649M</span>

4 0
4 years ago
Read 2 more answers
If an atom has 30 electrons and 35 neutrons, what is its approximate atomic mass? what is the name of this element?
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30 electrons = atomic number
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This means the name of the element is ZINC.

Hope this helped!
6 0
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