Answer:
The products are carbon dioxide and water
Explanation:
Step 1: Data given
Combustion = a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve O2 as one reactant.
Step 2: The complete combustion of C3H7OH:
For the combustion of 1-propanol, we need O2.
The products of this combustion are CO2 and H2O.
C3H7OH + O2→ CO2 + H2O
On the left side we have 3x C (in c3H7OH), on the right side we have 1x C (in CO2). To balance the amount of C, we have to multiply CO2 on the right side by 3
C3H7OH + O2→ 3CO2 + H2O
On the left side we have 8x H (in C3H7OH) and 2x on the right side (in H2O). To balance the amount of H, we have to multiply H2O, on the right side by 4.
C3H7OH + O2→ 3CO2 + 4H2O
On the left side we have 3x O (1x in C3H7OH and 2x in O2), on the right side we have 10x O (6x in CO2 and 4x in H2O).
To balance the amount of O on both sides, we have to multiply C3H7OH by 2, multiply O2 by 9. Then we have to multiply 3CO2 by 2 and 4H2O by 2. Now the equation is balanced.
2C3H7OH + 9O2→ 6CO2 + 8H2O
For 2 moles propanol, we need 9 moles of O2 to produce 6 moles of CO2 and 8 moles Of H2O
The products are carbon dioxide and water
Answer:
A. The actual number of atoms in a molecule
Explanation:
Molecular formula is simply defined as a type of chemical formula that describes the type and number of atoms present in a single molecule of a compound.
Looking at the options, the correct answer is option A.
<u>Analysing the Question:</u>
We are given the balanced equation:
C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O
from this equation, we can say that: <em>for every 1 mole of Glucose, we need 6 moles of Oxygen</em>
<u>Moles of Glucose used in the reaction:</u>
Molar mass of Glucose = 180 grams / mol
Given mass of Glucose = 1 gram
Mole of Glucose = Given mass / Molar mass
Moles of Glucose = 1 / 180 moles
<u>Mass of Oxygen required:</u>
We know that for every mole of Glucose, we need 6 moles of Oxygen
So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen
Mass of 1 / 30 moles of Oxygen:
Mass = Molar mass * number of moles
Mass of Oxygen = 32 * 1/30
Mass of Oxygen = 32 / 30
Mass of Oxygen = 1.06 grams
