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Dominik [7]
3 years ago
14

The position of the equilibrium for a system where K = 6.4 × 10 9 can be described as being favoring ________________

Chemistry
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

to the right (products side)

Explanation:

The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:

a A + b B → c C + d D

The equilibrium constant expression is:

K = \frac{[C]^{c} [D]^{d}  }{[A]^{a} [B]^{b}  }

A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).

Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.

Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.

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3 years ago
Type the correct answer in the box. Express your answer to three significant figures. Iron(II) chloride and sodium carbonate rea
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Answer:

The reaction can produce 287 grams of iron(II) carbonate

Explanation:

To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-

<em>Moles FeCl2:</em>

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As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles

<em>Mass FeCO3:</em>

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<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>
5 0
2 years ago
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