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Dominik [7]
3 years ago
14

The position of the equilibrium for a system where K = 6.4 × 10 9 can be described as being favoring ________________

Chemistry
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

to the right (products side)

Explanation:

The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:

a A + b B → c C + d D

The equilibrium constant expression is:

K = \frac{[C]^{c} [D]^{d}  }{[A]^{a} [B]^{b}  }

A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).

Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.

Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.

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