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Sloan [31]
3 years ago
9

Carbonic anhydrase is strongly inhibited by the drug acetazolamide, which is used as a diuretic (i.e., to increase the productio

n of urine) and to lower excessively high pressure in the eye (due to accumulation of intraocular fluid) in glaucoma.
a. True
b. False
Chemistry
1 answer:
gregori [183]3 years ago
3 0

Answer:

a. True

Explanation:

There is strong inhibition of Carbon Anhydrase by Aceta-zolamide Carbonic Anhydrase. The drug acetazolamide is used as diuretic which increase the urine production in human body. It lowers pressure in eye in glaucoma.

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mixas84 [53]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The best example of how electromagnetic energy is used in everyday life is <span>a patient receiving an X-ray in a hospital</span>
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Identify the functional groups present in each molecule.
Colt1911 [192]

Answer:

Carbon 3 is double bonded to an oxygen and attached to carbon 2 and carbon 4. :

Answer: Carbonyl group ( Ketone or aldehyde)

Carbon 17 is attached to an oxygen, which is attached to a hydrogen. :

Answer: Carboxyl group (Carboxylic acid)

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5 0
3 years ago
How many electrons are present in 4He2+?
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4 and 2 electrons are present.
4 0
3 years ago
How many grams of helium must be released to reduce the pressure to 65 atmatm assuming ideal gas behavior? Express the answer in
lyudmila [28]

The question is incomplete, here is the complete question:

How many grams of helium must be released to reduce the pressure to 65 atm assuming ideal gas behavior. Note : 334-mL cylinder for use in chemistry lectures contains 5.209 g of helium at 23°C.

<u>Answer:</u> The mass of helium released is 1.6 grams

<u>Explanation:</u>

We are given:

Mass of helium in the cylinder = 5.209 g

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas  = 65 atm

V = Volume of the gas  = 334 mL = 0.334 L   (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = ?

M = Molar mass of helium gas  = 4 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 23^oC=[23+273]K=296K

Putting values in above equation, we get:

65atm\times 0.334L=\frac{w}{4g/mol}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 296K\\\\w=\frac{65\times 0.334\times 4}{0.0821\times 296}=3.573g

Mass of helium released = (5.209 - 3.573) g = 1.636 g = 1.6 g

Hence, the mass of helium released is 1.6 grams

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3 years ago
How much energy is needed when 1.27 moles of sulfur reacts with excess
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Answer:

well what do you think it is

Explanation:

huh?..

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