<span>The pH scale is a logarithmic scale. Each change of 1 unit in pH represents a 10-fold change in hydrogen ion concentration. As the pH gets smaller the hydrogen ion concentration gets larger. Since you have gone from pH 5 to pH 3 there is a 100-fold increase in [H+].
For pH = 5; [H+] = antilog 10^-pH = 1.0 x 10^-5 M
For pH = 3; [H+] = antilog 10^-pH = 1.0 x 10^-3 M
(1.0 x 10^-3)/(1.0 x 10^-5) = 1.0 x 10^2 hope this helps</span>
No, the two isotopes of lithium-6 and lithium-7 are not equally common.
The more plentiful isotope would be lithium-7.
This can be easily demonstrated by assuming that both isotopes were equally common. If that were the case, the average atomic mass would be (6 + 7)/2 = 6.5 amu. Now compare that value if they were both equal to the actual value found in nature. The value found in nature is 6.941 amu which is heavier than the 6.5 amu that would happen if they were equally common. Since the natural value is heavier, that means that there has to be more of the heavier isotope than there is of the lighter one. Therefore lithium-7 is more common than lithium-6.
The correct answer is C
This is because acceleration is change in velocity over change in time
Velocity is speed and direction, because they spin in a circle their direction changes. Therefore do does the acceleration
Answer:
The the empirical formula for magnesium chloride based on this experiment will be
Explanation:
Given that,
Mass of Mg = 0.50 g
Mass of magnesium chloride found = 1.99 g
Let the formula of magnesium chloride be
We know that,
Molar mass of Mg= 24 g/mol
Molar mass of magnesium chloride = (24x+35.5y) g/mol
We need to calculate the moles of Mg
Using formula of moles
Put the value into the formula
We need to calculate the mole of magnesium chloride
Using formula of moles
Put the value into the formula
The reaction will be,
We need to calculate the value of x and y
Using number of moles of Mg in reactant and product
Moles of Mg atom in reactant=Moles of Mg atom in product
Hence, The the empirical formula for magnesium chloride based on this experiment will be