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Bogdan [553]
3 years ago
8

The perimeter of the square at the right is 48 in what is the area of the square at the right explain how you found your answer

Mathematics
1 answer:
irina1246 [14]3 years ago
5 0

ok so 48÷4 is each side since square sides are equal that is 12 ×12 which is a area of 144

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c

Step-by-step explanation:

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Find x and y in the following figure
Ipatiy [6.2K]

Y=145, I’m not sure about X

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What single decimal multiplier would you use to increase by 10% followed by a 16% decrease?
Neko [114]
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7 0
2 years ago
Please answer this correctly
iren2701 [21]

Answer:

10.71 yd

Step-by-step explanation:

First let's find the radius of the quarter circle.

area =\frac{1}{4} \pi {r}^{2} \\  7.065 = \frac{1}{4} *3.14 {r}^{2}  \\  \frac{7.065}{3.14}  = \frac{1}{4} * \frac{3.14 {r}^{2} }{3.14}  \\  9 =  {r}^{2}  \\  \sqrt{9}  = r \\ 3 yd= r

Now let's find the arc length of this quarter circle.

\frac{90}{360}  \times 2\pi \: r \\  \frac{1}{4}  \times 2 \times 3.14 \times 3 \\  =  \frac{9.42}{4}  \\  = 4.71yd \\

Now let's find the perimeterperimeter \\  = arc \:  \: length + radius + radius \\  = 4.71 + 3 + 3 \\  = 10.71yd

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<em>brainliest</em><em> </em><em>appreciated</em>

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4 0
3 years ago
Read 2 more answers
Find the area of a square if the perimeter is equal to 38 in.
Misha Larkins [42]
Hello! I would love to help!

Alright! We know that perimeter is basically adding all the sides of a shape together. We also know that a square has 4 sides, so 38 is the result of 4 sides being added. Now, we also know that all sides of a square are even. So, to find one side of a square, we just need to do 38/4


38/4=9.5


Alright. So now we know one side of a square is 9.5 in. We know that in order to find area, we have to multiply length and width. We know that since all sides of a square are even, 9.5 is both our length and width. So, in order to find the area, we just have to multiply 9.5 by 9.5

9.5*9.5=90.25

Alright! So we have determined your answer!!!


90.25 or in fraction form 90 1/4 inches squared!

Hope this helped! Comment if you have questions!!
8 0
3 years ago
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