To find the difference of 5 1/8 and 2 1/5 I would first turn the mixed numbers into improper fractions. Therefore, I would have 41/8 - 11/5. Then, I would find a common denominator which would be 40. I would have 205/40 - 88/40 and I would end up with 117/40.
Can you please help me answer my question? I already asked it but it hasn't been answered. It is fro social studies: What were some accomplishments of Montezuma?
Answer:
a) about 0.7 seconds to 5.1 seconds.
b) Listed below.
Step-by-step explanation:
h - 1 = -5x^2 + 29x
h = -5x^2 + 29x + 1
a) We will find the amount of time it takes to get to 18 meters.
18 = -5x^2 + 29x + 1
-5x^2 + 29x + 1 = 18
-5x^2 + 29x - 17 = 0
We will then use the quadratic formula to find the answer.
[please ignore the A-hat; that is a bug]
= 
= 
= 
= 
and 
= 0.6616970714 and 5.138302929
So, the time period for which the baseball is higher than 18 metres ranges from about 0.7 seconds to 5.1 seconds.
b) Restrictions on the domain and range of the function are that the domain and range can never be negative, since time cannot be negative, and height cannot be negative. The height cannot exceed the vertex of the parabola, since that is the highest the ball will ever go. It cannot exceed that height since gravity will cause the ball to fall down.
Hope this helps!
Simplify the expression.
25x6−4
plz mark me as brainliest :)
Hello,
15 pieces of ribbon, each is 2.25 yards long.
15 x 2.25 = 33.75 yards of ribbon.
Hope this helped!
Answer:
After reflection over the x-axis, we have the coordinates as follows;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
Step-by-step explanation:
Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis
By reflecting over the x-axis, the y-coordinate is bound to change in sign
So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)
We simply go on to negate the value of the y-coordinate
Mathematically if we apply these to the given points, what we get are the following;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
