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Ivenika [448]
3 years ago
5

5 What is the effect of the author proposing athought experiment at the beginning of the text? ​

Computers and Technology
2 answers:
jekas [21]3 years ago
7 0

Answer:

Thought experiments are basically devices of the imagination. They are employed for various purposes such an entertainment, education, conceptual analysis, exploration, hypothesizing, theory selection, theory implementation, etc.

anygoal [31]3 years ago
4 0

Answer:

i dont know correct or not . then also i will.. sorry if the answer is wrong

Explanation:

text "Disease Central" in When Birds Get Flu by John DiConsiglio. In 1958, scientists at the CDC made their first trip overseas. A team went to Southeast Asia to respond to an epidemic of smallpox and cholera. The author uses this passage to help the reader focus on

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Anarel [89]

Answer:

Attend traings

Explanation:

Because if you do you can learn diffent waay to do it and choose your way that you like.

ANd do not obseve poeple who has it easy  

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Write any two merits and demerits of computer​
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On a rheostat the first terminal is connected to a
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5 0
3 years ago
g Write a program to sort an array of 100,000 random elements using quicksort as follows: Sort the arrays using pivot as the mid
shtirl [24]

Answer:

header.h->function bodies and header files.

#include<iostream>

#include<cstdlib>

#include<ctime>

using namespace std;

/* Partitioning the array on the basis of piv value. */

int Partition(int a[], int bot, int top,string opt)

{

int piv, ind=bot, i, swp;

/*Finding the piv value according to string opt*/

if(opt=="Type1 sort" || opt=="Type3 sort")

{

piv=(top+bot)/2;

}

else if(opt=="Type2 sort" || opt=="Type4 sort")

{

piv=(top+bot)/2;

if((a[top]>=a[piv] && a[top]<=a[bot]) || (a[top]>=a[bot] && a[top]<=a[piv]))

piv=top;

else if((a[bot]>=a[piv] && a[bot]<=a[top]) || (a[bot]>=a[top] && a[bot]<=a[piv]))

piv=bot;

}

swp=a[piv];

a[piv]=a[top];

a[top]=swp;

piv=top;

/*Getting ind of the piv.*/

for(i=bot; i < top; i++)

{

if(a[i] < a[piv])

{

swp=a[i];

a[i]=a[ind];

a[ind]=swp;

ind++;

}

}

swp=a[piv];

a[piv]=a[ind];

a[ind]=swp;

return ind;

}

void QuickSort(int a[], int bot, int top, string opt)

{

int pindex;

if((opt=="Type3 sort" || opt=="Type4 sort") && top-bot<19)

{

/*then insertion sort*/

int swp,ind;

for(int i=bot+1;i<=top;i++){

swp=a[i];

ind=i;

for(int j=i-1;j>=bot;j--){

if(swp<a[j]){

a[j+1]=a[j];

ind=j;

}

else

break;

}

a[ind]=swp;

}

}

else if(bot < top)

{

/* Partitioning the array*/

pindex =Partition(a, bot, top,opt);

/* Recursively implementing QuickSort.*/

QuickSort(a, bot, pindex-1,opt);

QuickSort(a, pindex+1, top,opt);

}

return ;

}

main.cpp->main driver file

#include "header.h"

int main()

{

int n=100000, i;

/*creating randomized array of 100000 numbers between 0 and 100001*/

int arr[n];

int b[n];

for(i = 0; i < n; i++)

arr[i]=(rand() % 100000) + 1;

clock_t t1,t2;

t1=clock();

QuickSort(arr, 0, n-1,"Type1 sort");

t2=clock();

for( i=0;i<n;i++)

arr[i]=b[i];

cout<<"Quick sort time, with pivot middle element:"<<(t2 - t1)*1000/ ( CLOCKS_PER_SEC );

cout<<"\n";

t1=clock();

QuickSort(arr, 0, n-1,"Type2 sort");

t2=clock();

for( i=0;i<n;i++)

arr[i]=b[i];

cout<<"Quick sort time, with pivot median element:"<<(t2 - t1)*1000/ ( CLOCKS_PER_SEC );

cout<<"\n";

t1=clock();

QuickSort(arr, 0, n-1,"Type3 sort");

t2=clock();

for( i=0;i<n;i++)

arr[i]=b[i];

cout<<"Quick sort time and insertion sort time, with pivot middle element:"<<(t2 - t1)*1000/ ( CLOCKS_PER_SEC );

cout<<"\n";

t1=clock();

QuickSort(arr, 0, n-1,"Type4 sort");

t2=clock();

cout<<"Quick sort time and insertion sort time, with pivot median element:"<<(t2 - t1)*1000/ ( CLOCKS_PER_SEC );

return 0;

}

Explanation:

Change the value of n in the main file for different array size. Output is in the same format as mentioned, time is shown in milliseconds.

7 0
3 years ago
Use the variables k, d, and s so that they can read three different values from standard input--an integer, a double, and a stri
Nat2105 [25]

Answer:

The c++ program to implement the given scenario is shown below.

#include <iostream>

using namespace std;

int main() {

   // variables declared as mentioned

   int k;

   double d;

   string s;

   cout << " Enter an integer value, a double value, a string value in the mentioned order " << endl;

   cin >> k >> d >> s;

   // variables printed in reverse order

   cout << " Reverse order " << endl;

   cout << s << " " << d << " " << k << endl;

   // variables printed in original order

   cout << " Original order " << endl;

   cout << k << " " << d << " " << s << endl;

   return 0;

}

OUTPUT

Enter an integer value, a double value, a string value in the mentioned order  

12 45.67 brainly

Reverse order  

brainly 45.67 12

Original order  

12 45.67 brainly

Explanation:

1. All the variables are declared as mentioned in the question.

int k;

   double d;

   string s;

2. The user is prompted to enter values for integer, double and string variables respectively. The input is accepted in the order mentioned above.

cin >> k >> d >> s;

3. The input is accepted in a single line since this is mentioned in the scenario that variables should be printed in the order in which they are read.

4. These variables are displayed to the standard output in reverse order – string, double, integer. The variables are displayed with exactly one space in between them.

cout << s << " " << d << " " << k << endl;

5. Then, variables are displayed in the original order – integer, double, string. The variables are displayed with exactly one space in between them.

cout << k << " " << d << " " << s << endl;

7 0
3 years ago
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