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3 years ago

ASAP please I need help

Mathematics

1 answer:

Anna007 [38]3 years ago

6 0

In this problem, you are looking at a pair of similar trapezoids. So we must be looking for a ratio between a side in the smaller trapezoid and the corresponding side in the bigger trapezoid. We are given the lengths of AB and EF, which we can use to find this ratio.
But before we do anything we must convert units so that all units are the same. Let's convert the 60 feet into inches. 60 feet is 720 inches.
Next, set up the ratio I mentioned earlier. If we set up the ratio so that it is smaller:larger, we would get 4:720, which simplifies to 1:180. Basically what this ratio says is that every 1 inch in the smaller trapezoid corresponds to 180 inches in the bigger trapezoid. Now we can use this ratio to find the lengths of the sides in the bigger trapezoid. Just multiply all the lengths of the smaller trapezoid by 180 to get the lengths for the bigger trapezoid. Finally, when we have all our side lengths, divide them all by 12 (because 12 inches in 1 foot) to get the measurements in feet.

From here, I'll let you find the total length yourself.

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Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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