Answer:

Step-by-step explanation:
The hyperbola has x-intercepts, so it has a horizontal transverse axis.
The standard form of the equation of a hyperbola with a horizontal transverse axis is 
The center is at (h,k).
The distance between the vertices is 2a.
The equations of the asymptotes are
1. Calculate h and k. The hyperbola is symmetric about the origin, so
h = 0 and k = 0
2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6
a = 6/2 = 3
3. For 'b': The equation for the asymptote with the positive slope is

Thus, asymptote has the slope of

4. The equation of the hyperbola is

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.
Answer:
x = 9
Step-by-step explanation:
Step 1: Write equation
x + 8 = 17
Step 2: Solve for <em>x</em>
- Subtract 8 on both sides: x = 9
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
9 + 8 = 17
17 = 17
Answer:
A)310.18g/mol
B)84.9947g/mol
C)108.01 g/mol
d)159.7g /mole(Approx)
e)Coc12 g/mol
f) A1(OH)3 g/mol
g)83.9949 g/mol
h)197.9 g/mol
i)18.01529 g/mol
Step-by-step explanation:
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Answer:
56°
Step-by-step explanation:
First, the measure of angle GHE is equal to DFH. This means that you can set 98-6x=63-x, which becomes 5x=35 so x=7. Substitute 7 for x and you'll get DFH =63-7, which is 56.