All categories

3 years ago

HELP ME PLEASE :D :D

Mathematics

1 answer:

Talja [164]3 years ago

3 0

Make proportions and reduce them.
6/9=2/3
10/15=2/3
The two rectangles are similar proportionally with a ratio of 2:3.

Does that answer your question?

You might be interested in

What additional information is needed to prove the following triangles congruent by ASA?

lianna [129]

Answer:

angle B = angle C

Step-by-step explanation:

______________

7 0

3 years ago

Read 2 more answers

Which table shows a proportional relationship between x and y

Anettt [7]

Answer: A, and their proportional relationship is 5

Step-by-step explanation:

7 0

3 years ago

What is your hart rate if you count 18 beats in 15 seconds

inna [77]

Answer:

Your heart rate would be 72 beats per minute

Step-by-step explanation:

You need to get 60 minutes so If you multiply 15 by 4, its 60. Do the same for 18 and your heart rate is 72 beats per minute

4 0

3 years ago

Write the expression in complete factored form 2a(x-8) + q(x-8)

Mnenie [13.5K]

Answer:

x-8 out of 2a(x-8)+q(x-8)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

3 years ago