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3 years ago

-12=f-7 help please

Mathematics

2 answers:

Lisa [10]3 years ago

8 0

Answer:

f=-5

Step-by-step explanation:

1) Add 12 to both sides

2) You should get f=-5

lianna [129]3 years ago

6 0

Answer:

$\huge \boxed{F=-5}\checkmark$

Step-by-step explanation:

First, switch sides.

$\displaystyle F-7=-12$

Then, add by 7 from both sides of equation.

$\displaystyle F-7+7=-12+7$

Simplify, to find the answer.

$\displaystyle -12+7=-5$

$\huge \boxed{F=-5}$ , which is our answer.

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Which statement about 6x^2+7x-10 is true?

Anton [14]

Answer:

One of the factors is (x+ 2)

Step-by-step explanation:

$6 {x}^{2} + 7x - 10 \\ = (6x - 5)(x + 2)$

another factor is (6x - 5)

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3 years ago

7. A fish tank holds 180 gallons of water and is leaking at a rate of 8 gallons per day. A second fish

Hatshy [7]

Answer:

10 days

Step-by-step explanation:

180 - 8x = 160 - 6x

Solve X (which equals to 10 days)

(x = amount of days)

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3 years ago

Complete the square to write each ellipse in standard form. x^2 + 4y^2 + 24y = 32

Alexus [3.1K]

Answer: Okay, the answer is x^2/68+(y+3)^2/17=1.

Step-by-step explanation: Step. 1 Complete the square for 4y^2+24y: 4(y+3)^2−36.

Step 2. You’ll need to substitute 4(y+3)^2−36 for 4y^2+24y in the equation x^2+4y^2+24y=32: x^2+4(y+3)^2–36=32.

Step 3. So you’ll need to move –36 to the right side of the equation by adding 36 to the both sides: x^2+4(y+3)^2=32+36.

Step 4 You add 32 and 36: x^2+4(y+3)^2=68.

Step 5. You divide each term by 68 to make the right side equal to one: x^2/68+4(y+3)^2/68=68/68.

And step 6. You’ll need to simplify each term in the equation in order to set the right side equal to 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1: x^2/68+(y+3)^2/17=1. I hope you download Math-way app to calculate this ellipse in standard form to be extremely helpful, please mark me as brainliest, and have a great weekend! :D

6 0

3 years ago

Multiply. Answer as a fraction. Do not include spaces in your answer 5 1/6•(-2/5) =???

Ne4ueva [31]

Answer:

2 1/15

Step-by-step explanation:

Hey there!

Well to multiply,

5 1/6 • -2/5,

we need to make 5 1/6 improper

$\frac{31}{6} * -\frac{2}{5}$

31 * 2 = 62

6 * 5 = 30

$-\frac{62}{30}$

Simplified,

$\frac{31}{15} \\Proper\\2 \frac{1}{15}$

2 1/15

Hope this helps :)

3 0

3 years ago

Let divf = 6(5 − x) and 0 ≤ a, b, c ≤ 12. (a) find the flux of f out of the rectangular solid 0 ≤ x ≤ a, 0 ≤ y ≤ b, and 0 ≤ z ≤

dusya [7]

Continuing from the setup in the question linked above (and using the same symbols/variables), we have

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}(\nabla\cdot f)\,\mathrm dV$
$=\displaystyle6\int_{z=0}^{z=c}\int_{y=0}^{y=b}\int_{x=0}^{x=a}(5-x)\,\mathrm dx\,\mathrm dy\,\mathrm dz$
$=\displaystyle6bc\int_0^a(5-x)\,\mathrm dx$
$=6bc\left(5a-\dfrac{a^2}2\right)=3abc(10-a)$

The next part of the question asks to maximize this result - our target function which we'll call $g(a,b,c)=3abc(10-a)$ - subject to $0\le a,b,c\le12$ .

We can see that $g$ is quadratic in $a$ , so let's complete the square.

$g(a,b,c)=-3bc(a^2-10a+25-25)=3bc(25-(a-5)^2)$

Since $b,c$ are non-negative, it stands to reason that the total product will be maximized if $a-5$ vanishes because $25-(a-5)^2$ is a parabola with its vertex (a maximum) at (5, 25). Setting $a=5$ , it's clear that the maximum of $g$ will then be attained when $b,c$ are largest, so the largest flux will be attained at $(a,b,c)=(5,12,12)$ , which gives a flux of 10,800.

7 0

3 years ago