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ivann1987 [24]
3 years ago
15

How many 4' x 8' sheets of plywood are required to cover a floor that is 9 m by 16 m?

Mathematics
1 answer:
Xelga [282]3 years ago
8 0
Assuming no border or waste, 9m by 16 m translates to 29.52' x 52.49'.
use 32/8=4 sheets of plywood to cover the width on the 8' side.
For the length, use 52/4=13 pieces on the 4' side.  
This gives a total of 4*13=52 sheets.
The extra 0.49' x 29.52 can be covered using the extra from the last four sheets for the width.

Check: 
Area to be covered: 29.52*52.49=1550 sq. ft.
Area of plywood supplied = 52*4'x8'= 1664 sq. ft, > 1550 sq.ft.
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The missing dimension, radius = 6.00 m

Step-by-step explanation:

We are given the following things:

Height of cylinder, h  = 15 m

Radius of cylinder, r = z m (Labelled as z)

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Please refer to the image attached for the dimensions of cylinder as given.

We know that the volume of a cylinder can be given as:

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1696.5 = \pi z^{2} \times 15\\\Rightarrow z^{2} = 36.01\\\Rightarrow z = 6.00\ m

Hence, The missing dimension, radius = 6.00 m

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