Question

How many atoms and ions does lithium sulfite have?

Answer 1

Answer:

Hence the ions per mole are:

$Li^{+}= 2 ions$

$SO_{3}^{2-}(aq)= 1 ions$

In one mole of Li2SO3 , the number of the atoms are

$N_{a}=6.022\times 10^{23}$

Explanation:

The formula of  lithium sulfite is Li2SO3.

$Li_{2}SO_{3}$

It contain Li+ and SO3(2-) ions.This can be represented by :

$Li_{2}SO_{3}(s)\rightarrow 2Li^{+}(aq) +SO_{3}^{2-}(aq)$

Hence one mole of Li2SO3 will give 2 Li+ ions and 1 SO3 (2-) ion.

Hence the ions per mole are:

$Li^{+}= 2 ions$

$SO_{3}^{2-}(aq)= 1 ions$

Number of atoms in  lithium sulfite depends upon the mass of the Li2SO3 present .

Li2SO3 = 93.94 g/mole

This mass is equal to 1 mole of Li2SO3

Now 1 mole of any substance contain Na atoms . This is known as Avogadro Number.

$N_{a}=6.022\times 10^{23}$

Hence , if 1 mole of Li2SO3 is present then it contains Na atoms

If other then 1 mole present then number of atoms are calculated by:

$Number\ of\ Atoms=Moles\times (N_{a})$

Here n = number of moles

if the mass of the compound is given then first calculate the number of moles.

$Moles=\frac{mass}{Molar\ mass}$