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fomenos
3 years ago
11

HELP HELP URGENT STRONG ACIDS AND BASES

Chemistry
1 answer:
leonid [27]3 years ago
3 0

Answer:

Solution A is correct.

Explanation:

Strong acids or bases are assumed to dissociate completely when in a aqueous solution.

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Select the correct answer.
Zarrin [17]

Answer:

C.

Explanation:

A. C - 6 electrons - 1s2 2s2 2p2

B. O - 8 electrons - 1s2 2s2 2p4

C. N - 7 electrons - 1s2 2s2 2p3

D. Be - 4 electrons - 1s2 2s2

4 0
3 years ago
Which phrase is the best definition for the word common in environmental science?
andreev551 [17]
I believe that the best definition of the word common in environmental science is a typical resource. A typical resource is a resource that is not hard to find and is very common. The answer to the question will hence be A.
The answer could not be the other three choices because a shared resource is a resource that is used by more than one organism in the environment. A worthless resource is one that has no use in the environment while a rare resource is one that is hard to find.
7 0
3 years ago
Read 2 more answers
An element has this information:
SVETLANKA909090 [29]

Answer:

hydrogen

Explanation:

5 0
3 years ago
99 POINTS PLZ HELP
Kitty [74]
D. two identical daughter cells Diploid cells
Mitosis occurs more in your body since it changes, modifies and requires cell division at maximum rate in many useful situations with the stand to a particular system and organ.

6 0
3 years ago
Read 2 more answers
A sample of Ammonia gas at 650mmHg and 15 degree has a mass of 56.8g.calculate the volume occupied by the gas. Take N=14, H=1,R=
avanturin [10]

Answer:

The first thing we have to do is change and state all the units so that we can use our ideal gas law equation (PV = nRT).

650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.

650 \ mmHg \ * \ \frac{101kPa}{760 mmHg} = 86 \ kPa

P = 86kPa

T = 15°C + 273K = 288K

R (Gas constant) = 8.31 kj/mol  

Molar mass of Ammonia (NH_{3}) = (1 x 3) + (14) = 17g/mol

n (moles) = \frac{mass}{molar \ mass} = \frac{56.8}{17} = 3.34 mol

V = ?

Rearrange the equation to solve for Volume:

V = \frac{nRT}{P}

Substitute the values inside:

V = \frac{(3.34)(8.31)(288)}{(86)} = 93 L (rounded)

<u>Therefore 93 L of volume is occupied by the ammonia gas.</u>

<u></u>

4 0
2 years ago
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