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netineya [11]
3 years ago
15

A cell that a user is typing words or numbers into is called the ________  cell.

Computers and Technology
2 answers:
NeX [460]3 years ago
7 0
Cell content or Content value
Paladinen [302]3 years ago
3 0

Answer:

I think active cell

Explanation:

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Give an example of how loops are used in programming Kturtle​
tankabanditka [31]

Answer:

Explanation:

KTurtle is an educational programming environment for turtle graphics. It is released under the open-source GNU General Public License and is part of the KDE Project since KDE3. KTurtle includes an IDE and a programming language which is loosely based on Logo and is intended for teaching programming.

5 0
2 years ago
30 points) Suppose you are given a string containing only the characters ( and ). In this problem, you will write a function to
navik [9.2K]

Answer:

The screenshot is attached below

Explanation:

The below program check balence of paranthesis using stack.

if the input charecter is ( then push to stack

if the input charecter is ) then pop top element and compair both elements for match.

Program:

public class Main

{

static class stack // create class for stack

{

int top=-1; // initialy stack is empty so top = -1

char items[] = new char[50]; // Create an array for stack to store stack elements

 

void push(char a) // Function push element to stack

{

if (top == 49) // chack stack is full ?

{

System.out.println("Stack full");

}

else

{

items[++top] = a; // increment the array index and store the element

}

}

 

char pop() // function to return the elements from stack

{

if (top == -1) // check the stack is empty

{

System.out.println("Empty stack");

return '\0';

}

else

{

char element = items[top]; // return the top element

top--; // Decrement the array index by one

return element;

}

}

 

boolean isEmpty() // Check the stack is empty or not

{

return (top == -1) ? true : false;

}

}

static boolean isMatch(char character1, char character2) // Check the input charecters are matching pairs or not

{

if (character1 == '(' && character2 == ')') // If they match return true

return true;

else

return false;

}

 

static boolean isBalanced(String parantheses) // check the input string is balenced or not

{

char[] exp = new char[parantheses.length()]; // Create a charecter array

for (int i = 0; i < parantheses.length(); i++) { // Convert the string parantheses to charecter array

exp[i] = parantheses.charAt(i);

}

stack st=new stack(); // Declare an empty character stack    

for(int i=0;i<exp.length;i++)

{  

if (exp[i] == '('))   // if input charecter is '(' push to stack

st.push(exp[i]);

if (exp[i] == ')') // if input charecter is ')' pop top element from stack

{

if (st.isEmpty())

{

return false;

}

 

else if ( !isMatch(st.pop(), exp[i]) ) // Call isMatch function

{

return false;

}

}

 

}

 

if (st.isEmpty())

return true; //balanced

else

{

return false; //not balanced

}

}

 

 

public static void main(String[] args)

{

 

System.out.println(isBalanced("()()()")); // Output true if string is balenced

 

}

 

}

Screenshot:

5 0
2 years ago
Which steps will create a new blank word document
mrs_skeptik [129]

Answer:

Open word

File > New

Select a template

8 0
3 years ago
( Game Design) The companies who get video games out to consumers are called:
Bad White [126]

Answer:

They are called video game publishers

Explanation:

A video game publisher is responsible for financing a video game’s development, marketing, and release of the game to the consumers. Basically, they are the ones who manage the business end of the gaming field. If the video game company is well established, the publishers of that company will be the ones to distribute while some smaller companies will hire distribution companies to distribute the games for them

3 0
3 years ago
Write a program that generates 100 random numbers and keeps a count of how many of those random numbers are even and how many of
Anvisha [2.4K]

Answer:

import random

numbers = []

even = 0

odd = 0

for i in range(100):

   numbers.append(random.randint(1, 200))

for i in range(100):

   if numbers[i] % 2 == 0:

       even += 1

   else:

       odd += 1

print("Even:", even)

print("Odd:", odd)

Explanation:

Gg ez.

8 0
2 years ago
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