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3 years ago

13

Solve for x: 5x-34 = 2x-4

1 answer:

LUCKY_DIMON [66]3 years ago

3 0

Answer:

x = 10

Step-by-step explanation:

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Which best describes the incenter of a triangle?

zhannawk [14.2K]

The correct answer of the given question above about the incenter of a triangle is option B. The statement that best describes the incenter of a triangle is that, it is the point where the three angle bisectors of the triangle intersect. In geometry, an incenter of a triangle is described as the triangle center.

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3 years ago

Read 2 more answers

Nicole has $20 to spend on dinner for herself. She wants to tip 20% on the amount of her meal. Which of the following are amount

Sophie [7]

Answer:

Total amount spent for meal = $16.65

Step-by-step explanation:

Given:

Amount spent on dinner = $20

Tip = 20%

Find:

Total amount spent for meal

Computation:

Total amount spent for meal = Amount spent on dinner / (1+tip)

Total amount spent for meal = 20 / 1.2

Total amount spent for meal = 16.666

Total amount spent for meal = $16.65

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3 years ago

A triangle has sides of length 48 mm, 5cm and 1.4 cm.

cricket20 [7]

Answer:

<u><em>The triangle is a right-angled triangle. </em></u>

Step-by-step explanation:

<em>Hi there,</em>

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<em>I have included the answers as image format to the answers.</em>

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5 0

2 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago

STOP SCROLLING HELP ME PLSSSSSS!

quester [9]

Answer:

use proportions??

Step-by-step explanation:

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d

k

h

o

w

t

o

do

this i am only in 5th grade yikes

5 0

3 years ago